IN java Create a New Java Project called LastNameDuplicate. //Given an array of N elements with...

IN java

Create a New Java Project called LastNameDuplicate.

//Given an array of N elements with each element between 1 and N, write a program to determine whether there are any duplicates.

//You must prompt the user for the array elements.

//Display the contents of the array, along with the values that are duplicated and how many times they appeared in the array.

//NOTE: N should be at least 15. Input Validation: Verify that each element entered has a value between 1 and N. If an incorrect value is entered, continuously prompt for a new value. This should not halt or terminate your program.

Expert Solution

Java Program:

/* Java Program that reads elements in to array and displays duplicate count */

import java.util.*;

class Duplicates
{
   public static void main(String args[])
   {
       Scanner sc = new Scanner(System.in);

       int i, j;

       //Reading number of elements
       System.out.print("\n Specify number of elements: ");
       int N = sc.nextInt();

       //Array to hold input elements
       int[] arrayElements = new int[N];

       //Reading integers from the console
       System.out.println("\n Enter array elements: ");

       for (i = 0; i < N; i++)
       {
           //Loop till user enters a valid value
           do
           {
               //Reading value
               arrayElements[i] = sc.nextInt();
           }while(arrayElements[i] < 1 || arrayElements[i] > N);
       }

       //Printing array elements
       System.out.println("\n\n Array Elements: \n");
       for(i=0; i<N; i++)
       {
           System.out.print(" \t " + arrayElements[i]);
       }

       int temp;

       //Sorting array
       for(i=0; i<N; i++)
       {
           for(j=i+1; j<N; j++)
           {
               //Comparison
               if(arrayElements[i] > arrayElements[j])
               {
                   //Swapping
                   temp = arrayElements[i];
                   arrayElements[i] = arrayElements[j];
                   arrayElements[j] = temp;
               }
           }
       }

       boolean duplicate;
       int count;

       System.out.println("\n\n");

       //Searching for duplicate elements and storing count
       for (i = 0; i < N;)
       {
           duplicate = false;
           count = 1;

           //Searching over next position elements
           for (j = i+1; j < N; j++)
           {
               //If there is no match then break loop
               if(arrayElements[j] != arrayElements[i])
                   break;

               //Comparing elements
               if (arrayElements[i] == arrayElements[j] && j!=i)
               {
                   //Incrementing count
                   count ++;
                   duplicate = true;
               }
           }

           //Printing duplicate element
           if(duplicate)
           {
               i = i+count-1;
               System.out.println("\n Element: " + arrayElements[i] + " \t " + count + " times \n");
           }
           else
               i = i+1;
       }
   }
}

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Sample Output:

venereology answered 4 months ago

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