In: Statistics and Probability
2. We want to model the daily movement of a particular stock (say Amazon, ticker = AMZN) using a homogenous markov-chain. Suppose at the close of the market each day, the stock can end up higher or lower than the previous day’s close. Assume that if the stock closes higher on a day, the probability that it closes higher the next day is 0.58. If the stock closes lower on a day, the probability that it closes higher the next day is 0.46.
(a) What is the 1-step transition matrix? (Let 1 = higher, 2 = lower)
(b) On Monday, the stock closed higher. What is the probability that it will close higher on Thursday (three days later)
Answer:
Given that:
Suppose at the close of the market each day, the stock can end up higher or lower than the previous day’s close. Assume that if the stock closes higher on a day, the probability that it closes higher the next day is 0.58. If the stock closes lower on a day, the probability that it closes higher the next day is 0.46
a) What is the 1-step transition matrix? (Let 1 = higher, 2 = lower)
1 step transition matrix (A) is as follows
| lower | higher | |
| higher | 0.58 | 0.42 | 
| lower | 0.46 | 0.54 | 
b) On Monday, the stock closed higher. What is the probability that it will close higher on Thursday (three days later)
To calculate the probability for 3 days ahead we need to multiply matrix A with itself twice.
Thus A^3 = A*A*A is given as :
| 0.58 | 0.42 | 
| 0.46 | 0.54 | 
*
| 0.58 | 0.42 | 
| 0.46 | 0.54 | 
*
| 0.58 | 0.42 | 
| 0.46 | 0.54 | 
=
| 0.5296 | 0.4704 | 
| 0.5152 | 0.4848 | 
*
| 0.58 | 0.42 | 
| 0.46 | 0.54 | 
=
| 0.5235 | 0.4764 | 
| 0.5217 | 0.4781 | 
Thus the probability that stock will close higher on Thursday given the stock closed higher on Monday is 1,1 the element of the matrix A^3 = 0.5235