In: Advanced Math
Let R be the relation on Z+× Z+ such that (a, b) R (c, d) if and only if ad=bc. (a) Show that R is an equivalence relation. (b) What is the equivalence class of (1,2)? List out at least five elements of the equivalence class. (c) Give an interpretation of the equivalence classes for R. [Here, an interpretation is a description of the equivalence classes that is more meaningful than a mere repetition of the definition of R. Hint: Look at the ratio a/b corresponding to (a, b).
Given that,
R is the relation on Z+ * Z+ . (a,b) R(c,d)<=> ad=bc
(a)To prove:
R is equivalence relation
proof:
For equivalence relation we have to prove reflexive, symmentric and transistive.
Reflexive:
Consider (a,b)R . (a,b) R(a,b) is reflexive because ab=ab.
Symmentric:
Consider (a,b) and (c,d) R . Given that ad=bc and obviously bc=ad. Therefore, R is symmentric i.e., (a,b) R(c,d) =(c,d) R (a,b) .
Transistive:
Consider (a,b) ,(c,d) and (e,f) R.
(a,b)R(e,f) is af=be=>a/b=e/f ----(1)
(e,f)R(c,d) is ed=fc => e/f=c/d -------(2)
From (1) and (2)
a/b=c/d
ad=bc =>(a,b)R(c,d)
Therefore ,R is transistive.
R is an equivalence relation.
(b) The equivalence class of (1,2)in R is { (2,4),(3,6),(4,8),(5,10),(6,13)}
Because 1/2 = 2/4 = 3/6 = 4/8 = 5/10 = 6/12
(c) Equivalence class is the quotient set created from the relation divided by ~ .
R/~= Z+* Z+ /~
a/b~c/d is the equivalence class of R
It is also written as
R is the equivalence class of element (a,b)
{x R|x~ (a,b)}