Question

In: Biology

DNA sequence of wild type gene A and a mutant is shown below. 1. Transcribe and...

DNA sequence of wild type gene A and a mutant is shown below.

1. Transcribe and translate the wild type and mutant proteins.

2. Classify the type(s) of mutation(s) in gene A the mutant has.

3. Design a primer pair to generate a PCR fragment of any size from the wild type sequence. Write the primer pair and mark the 5’ and 3’ of each primer sequence.

wild-type gene

5’ TAG|ACC|ATG|CCA|GTA|AAT|TTA|CGA|TGA|CA 3’

3’ ATC|TGG|TAC|GGT|CAT|TTA|AAT|GCT|ACT|GT 5’

mutant 2

5’ TAG|ACC|ATG|CCA|GTA|AAT|ATG|TTA|CGA|TGA|CA 3’

3’ ATC|GGG|TAC|GGT|CAT|TTA|TAC|AAT|GCT|ACT|GT 5

Expert Solution

Transcription or synthesis of mRNA occur from 5' to 3'. For this the template DNA strand should be in 3' to 5' direction called antisense strand.

WILD TYPE PROTEIN: Template DNA strand--- 3'ATC|TGG|TAC|GGT|CAT|TTA|AAT|GCT|ACT|GT5'

Transcribed RNA strand---5'UAG|ACC|AUG|CCA|GUA|AAU|UUA|CGA|UGA|CA3'

Translated protein: 5'Gln-Thr-Met-Pro-Val-Asn-Leu-Arg3' (Here, UAG and UAA both this stop codon in some organism like acetabularia, Tetrahymena, Paramecium etc. code for Gln. While in them the third stop codon UGA is a stop codon. So after UGA no further translation take place).

MUTANT TYPE PROTEIN: Template DNA strand---3'ATC|GGG|TAC|GGT|CAT|TTA|TAC|AAT|GCT|ACT|GT5'

Transcribed RNA strand---5'UAG|CCC|AUG|CCA|GUA|AAU|AUG|UUA|CGA|UGA|CA3'

Translated protein: 5'Gln-Pro-Met-Gln-Val-Ans-Met-Leu-Arg3'

TYPE OF MUTATION:

Point mutation in 2nd triplet codon---G instead of T.
Addition of TAC triplet codon after 6th triplet codon compare to the wild type.

gladiator answered 2 years ago

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