DNA sequence of wild type gene A and a mutant is shown below. 1. Transcribe and...

DNA sequence of wild type gene A and a mutant is shown below.

1. Transcribe and translate the wild type and mutant proteins.

2. Classify the type(s) of mutation(s) in gene A the mutant has.

3. Design a primer pair to generate a PCR fragment of any size from the wild type sequence. Write the primer pair and mark the 5’ and 3’ of each primer sequence.

wild-type gene

5’ TAG|ACC|ATG|CCA|GTA|AAT|TTA|CGA|TGA|CA 3’

3’ ATC|TGG|TAC|GGT|CAT|TTA|AAT|GCT|ACT|GT 5’

mutant 2

5’ TAG|ACC|ATG|CCA|GTA|AAT|ATG|TTA|CGA|TGA|CA 3’

3’ ATC|GGG|TAC|GGT|CAT|TTA|TAC|AAT|GCT|ACT|GT 5

Solutions

Expert Solution

Transcription or synthesis of mRNA occur from 5' to 3'. For this the template DNA strand should be in 3' to 5' direction called antisense strand.

WILD TYPE PROTEIN: Template DNA strand--- 3'ATC|TGG|TAC|GGT|CAT|TTA|AAT|GCT|ACT|GT5'

Transcribed RNA strand---5'UAG|ACC|AUG|CCA|GUA|AAU|UUA|CGA|UGA|CA3'

Translated protein: 5'Gln-Thr-Met-Pro-Val-Asn-Leu-Arg3' (Here, UAG and UAA both this stop codon in some organism like acetabularia, Tetrahymena, Paramecium etc. code for Gln. While in them the third stop codon UGA is a stop codon. So after UGA no further translation take place).

MUTANT TYPE PROTEIN: Template DNA strand---3'ATC|GGG|TAC|GGT|CAT|TTA|TAC|AAT|GCT|ACT|GT5'

Transcribed RNA strand---5'UAG|CCC|AUG|CCA|GUA|AAU|AUG|UUA|CGA|UGA|CA3'

Translated protein: 5'Gln-Pro-Met-Gln-Val-Ans-Met-Leu-Arg3'

TYPE OF MUTATION:

Point mutation in 2nd triplet codon---G instead of T.
Addition of TAC triplet codon after 6th triplet codon compare to the wild type.

gladiator answered 1 year ago

Next > < Previous

Related Solutions

Please Transcribe and translate the normal sequence and the mutated sequence. Identify what type of DNA...

Please Transcribe and translate the normal sequence and the mutated sequence. Identify what type of DNA mutation occurred. (insertion, deletion, or substitution), and Identify what type of protein change resulted. (frameshift, missense, nonsense, or silent) 1) sequence: 3’ TAC CGA GGA ATG TAC GAC TGA ACG CTA ATT 5’. mutated sequence: 3’ AC CGA GGA ATG TAC GAC TGA ACG CTA ATT 5’. 2) sequence: 3’ TAC UUU CCU AAU AGG GGG GAC GCU UGU AGC ACG UAA 5’ mutated Sequence:...

Write sequence of the DNA strand that would be complementary to the DNA sequence shown below....

Write sequence of the DNA strand that would be complementary to the DNA sequence shown below. Label the 3' and 5' ends ofthe new strand. 3' T A C C G A T G G 5'

The sequence below represents the coding DNA strand of the start of a gene, including part...

The sequence below represents the coding DNA strand of the start of a gene, including part of the 5' untranslated region. (5')...TCGGAAGGAGGTAGCGGCAATGGGGAAAAGTATTGCTT...(3') In studying variants of this gene in disease, a nucleotide mutation of A→T was detected in the first base of the third codon. What effect would this mutation have? (When considering your answer, assume standard initiation of translation is numbered as codon 1.) Select one: a. Terminates translation b. No effect c. Disrupts ionic interactions at physiological pH...

Write down the DNA base sequence that is the complementary strand to the DNA sequence shown...

Write down the DNA base sequence that is the complementary strand to the DNA sequence shown below? (5') C G A C T T C G A G C T (3')

1) The WILDTYPE DNA/gene has the base sequence: 5’GTACTGCAT3’ (the antisense strand of the gene is...

1) The WILDTYPE DNA/gene has the base sequence: 5’GTACTGCAT3’ (the antisense strand of the gene is shown) The gene has undergone a mutation. The mutant DNA/gene has the base sequence: 5’GTACTCCAT3’ (the mutation is in BOLD) based on this information, answer the following 1a)What is the base sequence of mutant mRNA? Label the ends of the mRNA 1b) this mutation is most likely to be caused by: a. soot b. analogues c. X-Ray d. RNA polymerase e. ribosome (pick one)...

Suppose the DNA bases in a gene sequence follow the distribution: DNA base Probability A 1/3...

Suppose the DNA bases in a gene sequence follow the distribution: DNA base Probability A 1/3 C θ G 1/3 T 1/3 - θ In an experiment, the number of observed bases that are “A” or “C” in a gene sequence is x, and the number of observed bases that are “G” or “T” is y. The EM method is used to find the best value for the parameter θ. Describe the Expectation step for computing the expected numbers of...

Data Tables and Post-Lab Assessment Lab Questions 1. Transcribe the following DNA sequence: Hb A: 5’...

Data Tables and Post-Lab Assessment Lab Questions 1. Transcribe the following DNA sequence: Hb A: 5’ AGT AAC GGC AGA CTT CTC CTC AGG AGT CAG GTG CAC CAT 3’ 3'UCA UUG CCG UCU GAA GAG GAG UCC UCA GUC CAC GUG GUA 5' 2. Translate your new RNA sequence using the genetic code. Remember that when determining your amino acid sequence, the RNA sequence is read from 5’ to 3’. val- val -his- val- ser -ser- glu- glu- ser-ser-...

In a particular trait in Drosophila a cross between a mutant male and wild type female...

In a particular trait in Drosophila a cross between a mutant male and wild type female results in all wild type offspring, while a cross between a wild type male and a mutant female produces all mutant offspring. Describe the genetics of the trait.

A protein with a wild-type allele (Pwt) and protein with a mutant allele (Pm) are one...

A protein with a wild-type allele (Pwt) and protein with a mutant allele (Pm) are one amino acid in the position 12 of the protein chain. The mutant allele's sequence is 5'CTT whereras the wild-type allele's sequence is 5'CAT. Using an amino acid chart, find : Pwt in position #12 Pm in position #12

If the DNA sequence in the question above is at the BEGINNING of a gene, what...

If the DNA sequence in the question above is at the BEGINNING of a gene, what are the first 2 amino acids that will be joined at the ribosome? Remember there is a START codon. Use the information on this chart to answer the question. asparagine, alanine methionine, glutamine leucine, alanine alanine, lysine methionine, asparagine

Subjects