Question

In: Physics

A particle with a charge of 34 μC moves with a speed of 73 m/s in...

A particle with a charge of 34 μC moves with a speed of 73 m/s in the positive x direction. The magnetic field in this region of space has a component of 0.42 T in the positive ydirection, and a component of 0.83 T in the positive zdirection.

Part A

What is the magnitude of the magnetic force on the particle?

Express your answer using two significant figures.

F =

2.87•10−3

mN

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Part B

What is the direction of the magnetic force on the particle? (Find the angle measured from the positive z-axis toward the negative y-axis in the yz-plane.)

Express your answer using two significant figures.

θ =

∘

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Expert Solution

The magnetic force is given by the expression

remember the crus product is given by

and

a) In our case the particle is perpendicular to the magnetic field, as is show in the following figure

. For calculate our force, first we calcute

and then

the magnitud of the force

this tree vectors are showed in the following figure

b) As you can see the force's vector are only in towars the negative y-axis. The following ficgure represente the magnetic force in the yz plane

the angle measured from the negative y- axis is given by the expression

and the angle measured from the positive z-axis is calculated by indication of the following picture

genius_generous answered 4 months ago

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