A charged particle with negative charge Q=-5C is moving with the speed v=400 m/s and the...

A charged particle with negative charge Q=-5C is moving with the speed v=400 m/s and the direction of the velocity vector is at 60 degrees above horizontal as shown in the figure below. The particle moves in the presence of the magnetic field B produced by the long horizontal wire with current I=100 A flowing to the right.

A.)Find the magnitude of the magnetic field B at the location of the particle, 10 cm above the wire. Give your answer in mT (10^-3 T) units.

B.)Find the direction of the magnetic field at the location of the particle.

Pick the correct answer out of multiple options

horizontally to the right

pointing up

pointing out of the page

horizontally to the right

pointing into the page

pointing down

C.)Find the magnitude of the magnetic force acting on the moving particle. (in newtons)

D.) Find the magnitude of the horizontal component of the magnetic force. (in newtons)

E.)We assume that the x axis is horizontal in the paper plane pointing to the right, y axis is in paper plane pointing up, and z axiis is horizontal pointing out of paper plane. Thus x-z is the horizontal plane.

In this coordinate system determine the direction of the horizontal component of the magnetic force (vettical component is either along y or opposite to the y axis)

Pick the proper orientatioin of the horizontal force component.

along positive z direction (out of pager)

inclined at 30 degrees from negative z axis

along negative x direciton (to the left)

along +x axis (to the right)

inclinded at 60 degrees form positive z axis

inclined at 60 degrees from negative x axis

along negative z direction (into the page)

inclined at 30 degrees from positive x axis

Solutions

Expert Solution

genius_generous answered 1 year ago

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