an electron is moving with a speed of 2.9E5 m/s when it moves in the positive...

an electron is moving with a speed of 2.9E5 m/s when it moves in the positive x direction, it feels no force. When it moves in the positive y direction it experiences a force of 3.3E-14N that points in the negative z direction. What is the magnitude and direction of the magnetic field?

Solutions

Expert Solution

F = q (v B) ; denotes the cross product.

CASE I There is no force in the x-direction.

So v B = 0

vBsin = 0

So the angle between v and B is 0 i.e = 0.

====> the direction of the magnetic field is either along +x or -x direction.

CASE II Force when moving in y-direction.

F = q (v B)

3.3E-14 = 1.6E-19( 2.9E5 * B sin )

(Here = 90o as the direction of velocity is in y and that of B is along x)

Solving the above equation; we get B = 0.711 T

Also the direction of the force is along -ve z direction, so using the right hand thumb rule it can clearly be stated that the direction of the magnetic field is along +x axis.

So; B = 0.711 T along +ve x-axis.

genius_generous answered 1 hour ago

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