In the figure particle 1 of charge q1 = 0.93 μC and particle 2 of charge...

In the figure particle 1 of charge q₁ = 0.93 μC and particle 2 of charge q₂ = -2.96 μC, are held at separation L = 9.5 cm on an x axis. If particle 3 of unknown charge q₃ is to be located such that the net electrostatic force on it from particles 1 and 2 is zero, what must be the (a)x and (b)y coordinates of particle 3?

Expert Solution

Let us start the solution, by assuming that the charge is located at the origin (0,0) and the charge is located at a distance 9.5 cm to the right of .

The test charge 'Q' must be situation on x axis to the left of the . The reason behind this is as follows:

As the the strength of is lower than , the the repulsive force on Q ( directed outward) due to would be comparable to the attractive force (in order to have Net force to be Zero) on Q ( directed inward) due to , if the test charge Q situated closer to .

In order to have net force on Q to be equal to zero, we must have,

Now, if we equate both the force on Q, putting all the numbers, we will get that the test charge Q will be situated x=12.1 cm to the left of and 21.6 cm to the left of .

The x co ordinate of the test charge would be 12.1 cm and y co-ordinate would be zero.

genius_generous answered 2 years ago

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