In: Physics
The cylinder in the figure(Figure 1) has a moveable piston attached to a spring. The cylinder's cross-section area is 10 cm2, it contains 0.0048 mol of gas, and the spring constant is 1500 N/m. At 21 ∘C the spring is neither compressed nor stretched. How far is the spring compressed if the gas temperature is raised to 200 ∘C? Express your answer to two significant figures and include the appropriate units.
Hi,
Hope you are doing well.
We know that, Gases expand as temperature increases. Here, when temperature increases from 21oC to 200oC, gas inside the cylinder will expand and the piston will compress the spring attached to the piston.
lets assume that the gas inside the cylinder is an ideal gas.
We know that,
Work done,
where,
''
is the force acting on piston/spring.(N)
''
is the displacement of
piston/spring.(m)
let '' be the
change in volume of gas (m3) and '
' be the area of
cross-section of cylinder(m2).
where,
''
is the displacement of
piston/spring.(m)
also,
Where,
''
is the pressure of gas.(N/m2)
Multiplying both sides we get,
![]() |
Where,
''
is the Work done by gas to move piston/ work done by
spring(J).
''
is the pressure of gas.(N/m2)
'' is
the change in volume of gas (m3).
Also, we know that,
For an ideal
gas,
Where,
''
is the pressure of gas.(N/m2)
'' is the
Volume of gas.(m3)
'' is the
no.of moles of gas.
'' is the
Universal Gas Constant= 8.314 J/mol-K
''
is the temperature of gas.(K)
Differentiating both sides, we get,
![]() |
We know that work done by spring due to compression,
Where,
''
is the spring constant.(N/m)
''
is the displacement of
piston/spring.(m)
![]() |
WORK DONE BY GAS = WORK DONE TO
COMPRESS SPRING
Given that,
Spring constant,
No.of moles of gas,
Universal Gas Constant,
Initial temperature,
Final temperature,
Change in temperature,
![]() |
Hope this helped for your studies. Keep learning. Have a good day.
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