In: Chemistry
Phosphorus pentachloride decomposes according to the chemical equation PCL5(g)<--->PCl3(g)+Cl2(g). Kc=1.80 at 250 C. A 0.244 mol sample of PCl5(g) is injected into an empty 2.80 L reaction vessel held at 250 Celsius. Calculate the concentrations of PCl5(g) and PCl3(g) at equilibrium.
concentration of PCl5 = moles/ Volume in L= 0,244/2.8 M=0.087M
The reaction is PCl5 (g)<-------->PCl3(g)+Cl2(g), Kc= [PCl3] [Cl2]/[PCl5]
preparing the ICE Table
component PCl5 PCl3 Cl2
Initial concentration (M) 0.087 0 0
change -x x x
Equilibrium 0.087-x x x
hence Kc= x2/(0.087-x)= 1.8, This quadratic equation is solved using excel
when solved using excel, x= 0.0832, hence ay equilibrium, [PCl5]=0.087-0.0832=0.0038M, [PCl3]= [Cl2]=0.0832M