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Phosphorus pentachloride decomposes according to the chemical equation PCL5(g)<--->PCl3(g)+Cl2(g). Kc=1.80 at 250 C. A 0.244 mol...

Phosphorus pentachloride decomposes according to the chemical equation PCL5(g)<--->PCl3(g)+Cl2(g). Kc=1.80 at 250 C. A 0.244 mol sample of PCl5(g) is injected into an empty 2.80 L reaction vessel held at 250 Celsius. Calculate the concentrations of PCl5(g) and PCl3(g) at equilibrium.

Solutions

Expert Solution

concentration of PCl5 = moles/ Volume in L= 0,244/2.8 M=0.087M

The reaction is PCl5 (g)<-------->PCl3(g)+Cl2(g), Kc= [PCl3] [Cl2]/[PCl5]

preparing the ICE Table

component                                  PCl5                            PCl3                           Cl2

Initial concentration (M)                 0.087                           0                                0

change                                              -x                              x                                x

Equilibrium                                0.087-x                            x                               x

hence Kc= x2/(0.087-x)= 1.8, This quadratic equation is solved using excel

when solved using excel, x= 0.0832, hence ay equilibrium, [PCl5]=0.087-0.0832=0.0038M, [PCl3]= [Cl2]=0.0832M


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