Find the solution of the given initial value problem y'' + 4y = t^2 + 3e^t...

Find the solution of the given initial value problem y'' + 4y = t^2 + 3e^t + e^2t cost, y(0) = 0, y'(0) = 2,

using method of undetermined coefficients

Expert Solution

Colby Messinger answered 1 week ago

Find the solution of the given initial value problem. 2y''+y'-4y=0 ; y(0)=0 y'(0)=1

Find the solution of the initial value problem: y'' + 4y' + 20y = -3sin(2x), y(0)...

Find the solution of the initial value problem: y'' + 4y' + 20y = -3sin(2x), y(0) = y'(0) = 0

Find the solution to the following initial value problem y' -y = t - sint +...

Find the solution to the following initial value problem y' -y = t - sint + e^(2t); y(0) = 0

ﬁnd the solution of the given initial value problem 1. y''+4y=t2+3et, y(0) =0, y'(0) =2 2....

ﬁnd the solution of the given initial value problem 1. y''+4y=t2+3et, y(0) =0, y'(0) =2 2. y''−2y'+y=tet +4, y(0) =1, y'(0) =1

Solve the initial value problem: Y''-4y'+4y=f(t) y(0)=-2, y'(0)=1 where f(t) { t if 0<=t<3 , t+2...

Solve the initial value problem: Y''-4y'+4y=f(t) y(0)=-2, y'(0)=1 where f(t) { t if 0<=t<3 , t+2 if t>=3 }

1. solve the initial value problem. (t^(2)+1)y'+2ty=tant , y(0)=2 2.find the solution to this initial value...

1. solve the initial value problem. (t^(2)+1)y'+2ty=tant , y(0)=2 2.find the solution to this initial value problem. yy'=e^x+x , y(0)=y_0 y_0 is a nonzero constant.

Find the particular solution: y″−4y′+4y=(−11.5e^(2t))/(t^(2)+1)

Find the solution of the given initial value problem. y(4) + 2y''' + y'' + 8y'...

Find the solution of the given initial value problem. y(4) + 2y''' + y'' + 8y' − 12y = 12 sin t − e−t; y(0) = 7, y'(0) = 0, y''(0) = −1, y'''(0) = 2

Solve the given initial value problem by undetermined coefficients (annihilator approach). y'' − 4y' + 4y...

Solve the given initial value problem by undetermined coefficients (annihilator approach). y'' − 4y' + 4y = e^4x + xe^−2x y(0) = 1 y'(0) = −1

Solve the given initial-value problem. y'' + 4y' + 4y = (5 + x)e^(−2x) y(0) =...

Solve the given initial-value problem. y'' + 4y' + 4y = (5 + x)e^(−2x) y(0) = 3, y'(0) = 6 Arrived at answer y(x)=3e^{-2x}+12xe^{-2x}+(15/2}x^2e^{-2x}+(5/6)x^3e^{-2x) by using variation of parameters but it was incorrect.

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