ﬁnd the solution of the given initial value problem 1. y''+4y=t2+3et, y(0) =0, y'(0) =2 2....

ﬁnd the solution of the given initial value problem

1. y''+4y=t²+3e^t, y(0) =0, y'(0) =2

2. y''−2y'+y=te^t +4, y(0) =1, y'(0) =1

Expert Solution

First differential equation solve Using undetermined coefficient method. Second equation solve Using variation of parameter.

Colby Messinger answered 1 year ago

ﬁnd the solution of the given initial value problem 1. y''−2y'−3y=3te2t, y(0) =1, y'(0) =0 2....

ﬁnd the solution of the given initial value problem 1. y''−2y'−3y=3te2t, y(0) =1, y'(0) =0 2. y''+4y=3sin2t, y(0) =2, y'(0) =-1

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