Question

In: Math

1. solve the initial value problem. (t^(2)+1)y'+2ty=tant , y(0)=2 2.find the solution to this initial value...

1. solve the initial value problem.

(t^(2)+1)y'+2ty=tant , y(0)=2

2.find the solution to this initial value problem.

yy'=e^x+x , y(0)=y_0

y_0 is a nonzero constant.

Solutions

Expert Solution

milcah answered 2 years ago
Next > < Previous

Related Solutions

Solve the initial value problem: Y''-4y'+4y=f(t) y(0)=-2, y'(0)=1 where f(t) { t if 0<=t<3 , t+2...
Solve the initial value problem: Y''-4y'+4y=f(t) y(0)=-2, y'(0)=1 where f(t) { t if 0<=t<3 , t+2 if t>=3 }
Solve the laplace transform to solve the initial value problem. y"-6y'+9y=t. Y(0)=0, y'(0)=1
Solve the laplace transform to solve the initial value problem. y"-6y'+9y=t. Y(0)=0, y'(0)=1
Find the solution of the initial value problem y′′−2y′−3 y=15te2t, y(0)=2, y′(0)=0.
Find the solution of the initial value problem y′′−2y′−3 y=15te2t, y(0)=2, y′(0)=0.
Use Laplace transforms to solve the initial value problem: y''' −y' + t = 0, y(0)...
Use Laplace transforms to solve the initial value problem: y''' −y' + t = 0, y(0) = 0, y'(0) = 0, y''(0) = 0.
Find the solution of the given initial value problem: y′′′+y′=sec(t), y(0)=6, y′(0)=7, y′′(0)=−3
Find the solution of the given initial value problem: y′′′+y′=sec(t), y(0)=6, y′(0)=7, y′′(0)=−3
Solve the initial value problem. y'=(y^2)+(2xy)+(x^2)-(1), y(0)=1
Solve the initial value problem. y'=(y^2)+(2xy)+(x^2)-(1), y(0)=1
Find the solution of the given initial value problem. 2y''+y'-4y=0 ; y(0)=0 y'(0)=1
Find the solution of the given initial value problem. 2y''+y'-4y=0 ; y(0)=0 y'(0)=1
solve the following initial value problem y''+4y'=g(t),y(0)=0,y' (0)=1 if g(t) is the function which is 1...
solve the following initial value problem y''+4y'=g(t),y(0)=0,y' (0)=1 if g(t) is the function which is 1 on [0,1) and zero elsewhere
Find the solution to the following initial value problem y' -y = t - sint +...
Find the solution to the following initial value problem y' -y = t - sint + e^(2t); y(0) = 0
Solve the initial value problem: y''+2y'+y = x^2 , y(0)=0 , y'(0) = 0
Solve the initial value problem: y''+2y'+y = x^2 , y(0)=0 , y'(0) = 0
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT