In: Physics
Three point charges are positioned on the x -axis: +99.0 ? C at x = 0.00 cm, +89.0 ? C at x = 65.0 cm, and -26.0 ? C at x= 15.0 cm. What is the magnitude of the electrostatic force acting on the +99.0
Charges and their positions:
q1 = 99 * 10-6 C at x1 = 0 cm
q2 = 89 * 10-6 C at x2 = 65 cm = 0.65 m
q3 = -26 * 10-6 C at x3 = 15 cm = 0.15 m
k = 8.99 * 109 Nm2 / C2 is the Coulomb's force constant.
X component of the electric force acting on q1 is,
Fx = kq1q2 cos 180 / x22 + kq1q3 cos 0/ x32
Fx = - 8.99 * 109 * 99 * 10-6 * 89 * 10-6 / (0.65)2 + 8.99 * 109 * 99 * 10-6 * 26 * 10-6 / (0.15)2
Fx = 840.974 N
Since the charges are aligned on the x - axis, there is no Y component of the force and magnitude of the force F is,
F = Fx
F = 840.974 N