Question

In: Physics

3. Two 2.20-?C point charges are located on the x axis. One is at x =...

3.

Two 2.20-?C point charges are located on the x axis. One is at x = 1.57 m, and the other at x = -1.57 m. Determine the magnitude of the electric field on the y axis at y = 0.530 m. Answer in units of N/C.

4.Three identical point charges of charge q = 7.3 ?C are placed at the vertices (corners) of an equilateral triangle. If the side of triangle is a = 5.2m, what is the magnitude, in N/C, of the electric field at the point P in one of the sides of the triangle midway between two of the charges?

5.Four charges are placed at the corners of a square. If q₁ = 44.0 x 10^-9 C, q₂ = -24.0 x 10^-9 C, q₃ = 26.0 x 10^-9 C, q₄ = -46.0 x 10^-9 C and the side of the square is a = 0.32 m. What would be the magnitude of the electrical field in the middle of the square? Answer in units of N/C.

Expert Solution

3. Two 2.20-?C point charges are located on the x axis. One is at x = 1.57 m, and the other at x = -1.57 m. Determine the magnitude of the electric field on the y axis at y = 0.530 m.

electric field at Y(.53m) axis

= 9*10⁹*2.2*10^-6/root(1.57²+.530²)²<tan^-1 (.53/1.57) +9*10⁹*2.2*10^-6/root(1.57²+.530²)²<tan^-1 180-(.53/1.57)

= 7.2*10³<18.65⁰ + 7.2*10³<161.35⁰= 4.6*10³ <90 N/C

magintude = 4.6*10³ N/C

4.Three identical point charges of charge q = 7.3 ?C are placed at the vertices (corners) of an equilateral triangle. If the side of triangle is a = 5.2m, what is the magnitude, in N/C, of the electric field at the point P in one of the sides of the triangle midway between two of the charges?

distance between one corner and mid of oppisite side of the equilateral triangle

root(((5.2+5.2cos(60))/2)²+(5.2sin(60)/2)²) = 4.11 m

electric field at mid of side = 9*10⁹*7.3*10^-6/2.6²<60 + 9*10⁹*7.3*10^-6/2.6²<-120 +9*10⁹*7.3*10^-6/4.11²<150 = 9.72*10³ <60 + 9.72*10³ <-120 + 3.89*10³ <150 N/C

= 3.89*10³ <150⁰ N/C magnintude of the field at P = 3.89*10³ N

5.Four charges are placed at the corners of a square. If q₁ = 44.0 x 10^-9 C, q₂ = -24.0 x 10^-9 C, q₃ = 26.0 x 10^-9 C, q₄ = -46.0 x 10^-9 C and the side of the square is a = 0.32 m. What would be the magnitude of the electrical field in the middle of the square? Answer in units of N/C.

electric field at center of the squre

distance between corenr to center = .32/root(2) = .226 m

= 9*10⁹*44.0 x 10^-9/.226²<-45+9*10⁹*46.0 x 10^-9/.226²<-45 +9*10⁹*24.0 x 10^-9/.226²<45+9*10⁹*26.0 x 10^-9/.226²<45 = 7753.15<-45 + 8105.57<-45 +4229<45 + 4581.4<45 N/C

= 18141.7<-15.94⁰ N/C

genius_generous answered 5 months ago

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