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In: Physics

Two 53.0 x 10-9 C point charges are located on the x axis. One is at...

Two 53.0 x 10-9 C point charges are located on the x axis. One is at x = 0.35 m, and the other at x = - 0.35 m.

a) A third identical charge is placed on the y axis at y = 0.35 m. Find the magnitude of the force acting on this third charge? Answer in Newtons.

b) Now the third identical charge is placed on the y axis at y = 2 x 0.35 m. Find the magnitude of the force acting on this third charge? Answer in Newtons.

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Four charges are placed at the corners of a square. The side of the square is a = 0.30 m.

a) If the charge are identical and positive q = 21.0 x 10-9 C what would be the magnitude of the force acting on each of the charges? Answer in Newtons.

b) We change the charges by q1 = 21.0 x 10-9 C, q2 = 11.0 x 10-9 C, q3 = -12.0 x 10-9 C, q4 = -31.0 x 10-9 C. What would be the magnitude of the force acting on charge q3? Answer in Newtons.

c) We place the same charges at the corners of a rectangle of sides a and b (instead of a square). If b=2a/3 what would be the magnitude of the force acting on charge q3? Answer in units of Newtons.

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Two 2.20-?C point charges are located on the x axis. One is at x = 1.57 m, and the other at x = -1.57 m. Determine the magnitude of the electric field on the y axis at y = 0.530 m. Answer in units of N/C.

Solutions

Expert Solution

Two 53.0 x 10-9 C point charges are located on the x axis. One is at x = 0.35 m, and the other at x = - 0.35 m.

a) A third identical charge is placed on the y axis at y = 0.35 m. Find the magnitude of the force acting on this third charge? Answer in Newtons.here r = 0.494 m

F = kqq(1/0.4942 + 1/0.4942)

= 3.90 *10-6 N

b) Now the third identical c harge is placed on the y axis at y = 2 x 0.35 m.

here r = 0.782

F = kqq(1/0.7822 + 1/0.7822)

F = 1.557 *10-6 N

b.

Four charges are placed at the corners of a square. The side of the square is a = 0.30 m.

a) If the charge are identical and positive q = 21.0 x 10-9 C the magnitude of the force acting on each of the charges

F = kq1q2/r^2

F = 9*109(21.0 x 10-9)2(1/.32 +1/.32 + 1/.4242)

F = 1.102*10-6 N

b) We change the charges by q1 = 21.0 x 10-9 C, q2 = 11.0 x 10-9 C, q3 = -12.0 x 10-9 C, q4 = -31.0 x 10-9 C. the magnitude of the force acting on charge q3

F = k* -11.0 x 10-9*10-9( 21.0/.4242 + 12/.32 -31/.32)

F = 9.33*10-6 N

3. Two 2.20-?C point charges are located on the x axis. One is at x = 1.57 m, and the other at x = -1.57 m.

the magnitude of the electric field on the y axis at y = 0.530 m

E = kq/r^2 where r = 1.657 m

E = 9*10-9*2.2*10-6(1/1.6572 -1/1.6572)

E = 0


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