Question

In: Physics

Three point charges are on the x-axis: q1 at the origin, q2 at 3 m, and...

Three point charges are on the x-axis: q1 at the origin, q2 at 3 m, and q3 at 7 m.

A) Find the potential at the point (0, 4 m) if q1 = q2 = q3 = 2 µC. The Coulomb constant is 8.99 × 109 N · m2 /C 2 Answer in units of kV.

B) Find the potential at the point (0, 4 m) if q1 = q2 = 2 µC and q3 = −2 µC . Answer in units of kV.

C) Find the potential at the point (0, 4 m) if q1 = q3 = 2 µC and q2 = −2 µC . Answer in units of kV.

Solutions

Expert Solution

r1 = 4 m

r2 = sqrt(3^2+4^2) = 5 m


r3 = sqrt(7^2+4^2) = 8.1 m

A)


potential due to q1 , V1 = k*q1/r1 = 8.99*10^9*2*10^-6/4 = 4.495 KV

potential due to q2 , V2 = k*q2/r2 = 8.99*10^9*2*10^-6/5 = 3.596 KV


potential due to q3 , V3 = k*q3/r3 = 8.99*10^9*2*10^-6/8.1 = 2.22 KV


net potential V = V1 + V2 + V3 = 10.311 kV

---------------------------------------------------------


(B)

potential due to q1 , V1 = k*q1/r1 = 8.99*10^9*2*10^-6/4 = 4.495 KV

potential due to q2 , V2 = k*q2/r2 = 8.99*10^9*2*10^-6/5 = 3.596 KV


potential due to q3 , V3 = k*q3/r3 = -8.99*10^9*2*10^-6/8.1 = -2.22 KV


net potential V = V1 + V2 + V3 = 5.871 kV


--------------------------------------------------------

C)

potential due to q1 , V1 = k*q1/r1 = 8.99*10^9*2*10^-6/4 = 4.495 KV

potential due to q2 , V2 = k*q2/r2 = -8.99*10^9*2*10^-6/5 = -3.596 KV


potential due to q3 , V3 = k*q3/r3 = 8.99*10^9*2*10^-6/8.1 = 2.22 KV


net potential V = V1 + V2 + V3 = 3.119 kV

genius_generous answered 1 year ago
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