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A small coin, initially at rest, begins falling. If the clock starts when the coin begins...

A small coin, initially at rest, begins falling. If the clock starts when the coin begins to fall, what is the magnitude of the coin's displacement between t1 = 0.188 s and t2 = 0.845 s?

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A small coin, initially at rest, begins falling. If the clock starts when the coin begins to fall, what is the coin's displacement between t1=0.1498 s and t2=0.374 s?

Initial velocity, vi = 0 m/s

Displacement in t1 seconds:

y1 = vi * t + (1/2) a t^2

= vi * t1 + (1/2) g t1^2

= 0 * 0.1498 + 0.5 * 9.8 * 0.1498^2

= 0.109956196 m

Displacement in t2 seconds:

y2 = vi * t + (1/2) a t^2

= vi * t2 + (1/2) g t2^2

= 0 * 0.374 + 0.5 * 9.8 * 0.374^2

= 0.6853924 m

Displacement between t1 and t2 seconds:

?y = y2 - y1

= 0.575436204 m

= 0.5754 m

genius_generous answered 5 months ago

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