Question

A mountain climber stands at the top of a 50 m cliff that over hangs a calm pool of water. She throws two stones vertically downward 1.00 sec apart and observes that they cause a single splash. The first stone had an initail velocity of -2.00 m/s (a) how long after release of the first stone did the two stones hit the water? (b) what initail velocity must the second stone have had , given that they hit the water simultaneously? (c) what was the velocity of each stone at the instant it hit the water?

Answer 1

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A mountain climber stands at the top of a 50.0 m cliff that overhangs a calm pool of water. She throws two stones vertically downward 1.00 s apart and observes that they cause a single splash. The first stone had an initial velocity of -3.00 m/s.

(a) How long after release of the first stone did the two stones hit the water?
______ s

(b) What initial velocity must the second stone have had, given that they hit the water simultaneously?
_______m/s

(c) What was the velocity of each stone at the instant it hit the water?

first stone ______ m/s
second stone _____ m/s

1)

-50 = -4.9t^2 -3t

t = 2.90289 seconds <ANSWER

2)
Second stone has 1.90289 seconds

-50 = -4.9*(1.90289)^2 + v0*1.90289

v0 = -16.95 m/s <ANSWER

3)
Stone 1

v = at + v0
v = -9.8*2.90289 -3 = -31.448 m/s <ANSWER

v = at + v0
v = -9.8t - 16.95 = -35.598 m/s <ANSWER