A woman stands at the edge of a cliff and throws a rock horizontally over the...

A woman stands at the edge of a cliff and throws a rock horizontally over the edge with a speed of v₀ = 16.0 m/s. The rock leaves her hand at a height of h = 33.0 m above level ground at the bottom of the cliff, as shown in the figure. Note the coordinate system in the figure, where the origin is at the bottom of the cliff, directly below where the rock leaves the hand.

Write the equations for the x- and y-components of the velocity of the rock with time. (Use the following as necessary: t. Assume that v_x and v_y are in m/s and t is in seconds. Do not include units in your answers.)

v_x=

v_y=

Write the equations for the position of the rock with time, using the coordinates in the figure. (Use the following as necessary: t. Assume that x and y are in meters and t is in seconds. Do not include units in your answers.)

How long (in s) after being released does the rock strike the ground below the cliff? ___s

With what speed (in m/s) and angle of impact (in degrees clockwise from the +x-axis) does the rock land?

v_f=

θ=

Solutions

Expert Solution

1. i .............(3)

2. j ( downward) ....................(4)

3. i.................... (2)

4. ( -- j) ..........................(1)

5. t = 2.595s ..............................(5)

6. V_f = 30.04 m/s

genius_generous answered 1 year ago

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