Question

A student stands on the edge of a cliff and throws a stone horizantally over the edge with a speeed "v1". The cliff is "h" meters high. Given [h, v1]

a. The time for the stone to hit the ground

b. The horizantal distance the stone traveled while in the air.

c. The magnitude and direction of the stone's velocity just before hitting the ground

Answer 1

Solution:

Initial velocity in vertical direction = v_1y = 0

Initial velocity in vertical direction = v_1x = v₁

displacement in vertical direction = -h

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a)

Now using

Let "T" be the time to hit ground

...........................answer a.

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b)

Horizontal distance travelled = v_1x T = v₁ T =    ...........................answer b.

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c)

Velocity in horizontal direction remains constant so even just before hitting ground horizontal velocity = v₁

Velocity in vertical direction keeps changing due to acceleration and after time T is given by

So magnitude of velocity just before hitting ground is

...........................Magnitude

direction is given by

..................................Angle made with +x direction in anticlokwise manner.