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Prove that (m → s) → (¬s → ¬m) ⇔ 1 using Boolean algebra and Propositional...

Prove that (m → s) → (¬s → ¬m) ⇔ 1 using Boolean algebra and Propositional calculus

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Expert Solution

In first order logic, the conditional

A -> B A V B,

Using this,

(m->s) -> (s -> m)    (m->s) V (s -> m)

(m V s) V ( (s) V m)

(m V s) V ( m V s)

Now consider A = (s V m),

A V A

1

This completes our proof.

venereology answered 6 months ago
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