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Simplify the equation using Boolean algebra properties. F = xy + xy’z + x’yz

Simplify the equation using Boolean algebra properties.

F = xy + xy’z + x’yz

Solutions

Expert Solution

F = xy + xy'z + x'yz
= xy(z+z') + xy'z + x'yz
= xyz + xyz' + xy'z + x'yz
= (xyz + xyz + xyz) + xyz' + xy'z + x'yz
= (xyz + xyz') + (xyz + xy'z) + (xyz + x'yz)
= (xy(z+z')) + (xz(y+y')) + (yz(x+x'))
= (xy(1)) + (xz(1)) + (yz(1))
= xy + xz + yz
Answer: xy + xz + yz

venereology answered 1 year ago
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