Simplify the following Boolean expressions to the minimum number
of terms using the properties of Boolean algebra (show your work
and write the property you are applying). State if they cannot be
simplified
A. X’Y + XY
B. (X + Y)(X + Y’)
C. (A’ + B’) (A + B)’
D. ABC + A’B + A’BC’
E. XY + X(WZ + WZ’)
Simplify the following Boolean expressions to the minimum number
of terms using the properties of Boolean algebra (show your work
and write the property you are applying). State if they cannot be
simplified.
A. A’B + AB
B. XY + X(WZ + WZ’)
C. X’Y’(X’+Y)(Y’+Y)
D. ABC + A’B + A’BC’
E. (A+B)(AC+AC’)+AB+B
Draw the circuit logic diagrams for both the original and
simplified expressions.
1. Use Boolean algebra to simplify the following Boolean
expressions to expressions containing a minimum number of
literals:
(a) A’C’ + A’BC + B’C
(b) (A + B + C)’(ABC)’
(c) ABC’ + AC
(d) A’B’D + A’C’D + BD
(e) (A’ + B)’(A’ + C’)’(AB’C)’
(f) (AE + A’B’)(C’D’ + CD) + (AC)’
2. Obtain the truth table of the function F = (AB + C)(B + AC),
express the function F in sum-of-minterms and product-of-maxterms
forms, and express...
Use boolean algebra to prove that:
(A^- *B*C^-) + (A^- *B*C) + (A* B^- *C) + (A*B* C^-) + (A*B*C)=
(A+B)*(B+C)
A^- is same as "not A"
please show steps to getting the left side to equal the right
side, use boolean algebra properties such as distributive,
absorption,etc
Assume B is a Boolean Algebra. Prove the following statement
using only the axioms for a Boolean Algebra properties of a Boolean
Algebra.
Uniqueness of 0: There is only one element of B that is an
identity for +
please include all the steps.
1.) Simplify the following Boolean Expression to a
minimum number of literals.
(a'b' + c)(a + b + c')
a.)ab + a'b'c' + ac
b.)ac + abc + bc
c.)ac + a'b'c' + bc
d.)a'c + abc + b'c
e.)None of the above
2.) Reduce to two literals.
wxy'z + w'xz + wxyz
a.) xz
b.) x'z
c.) xz'
d.) yz
e.) None of the above