In: Operations Management
The manager of an organic yogurt processing plant desires with a mean of 16 ounces +/- 0.5 ounces. The process has a mean of 15.9 ounces and a standard deviation of 1 ounce.
Now the management has redesigned the system and so the standard deviation of the process is reduced to 0.1 ounces.
1. UPPER = 16.6
LOWER = 15.5
PROCESS MEAN = 15.9
STANDARD DEVIATION = 1
CPK = MIN((UPPER - MEAN) / 3 * STANDARD DEVIATION), (MEAN - LOWER ) / 3 * STANDARD DEVIATION)
CPK = MIN((16.6 - 15.9) / 3 * 1), (15.9 - 15.5) / 3 * 1)
CPK = MIN(0.2333, 0.1333)
CPK = 0.133
SINCE CPK = 0.133 < 1, THE PROCESS IS NOT CAPABLE.
PROCESS CAPABILITY RATIO
UPPER = 16.6
LOWER = 15.5
STANDARD DEVIATION = 1
CP = (UPPER - LOWER ) / (6 * STANDARD DEVIATION)
CP = (16.6 - 15.5) / (6 * 1)
CP = 0.183
CP = 0.183 < 1, THE PROCESS IS NOT CAPABLE
2. A. UPPER = 16.6
LOWER = 15.5
PROCESS MEAN = 15.9
STANDARD DEVIATION = 0.1
CPK = MIN((UPPER - MEAN) / 3 * STANDARD DEVIATION), (MEAN - LOWER ) / 3 * STANDARD DEVIATION)
CPK = MIN((16.6 - 15.9) / 3 * 0.1), (15.9 - 15.5) / 3 *
0.1)
CPK = MIN(2.3333, 1.3333)
CPK = 1.333
SINCE CPK = 1.333 > 1, THE PROCESS IS CAPABLE
2. UPPER = 16.6
LOWER = 15.5
STANDARD DEVIATION = 0.1
CP = (UPPER - LOWER ) / (6 * STANDARD DEVIATION)
CP = (16.6 - 15.5) / (6 * 0.1)
CP = 1.833
CP = 1.833 > 1, THE PROCESS SHOWS HIGH CAPABILITY
B. CP, BEING A CENTERED PROCESS WOULD NOT BE AFFECTED BY THE CHANGE IN THE MEAN VALUE SINCE CP IS CALCULATED BY THE DIFFERENCE IN THE UPPER LIMIT / 6 * SIGMA
C. AS THE MEAN INCREASES, THE CPK WOULD FIRST INCREASE, THEN STABILIZE THEN START DECREASING AS THE PROCESS MOVES TOWARD THE UPPER CONTROL LIMIT.
D. THERE IS NO MAXIMUM VALUE THAT LIMITS THE CPK VALUE, BUT AN
EXTREMELY HIGH OR NEGATIVE VALUE OF CPK WOULD SUGGEST THAT THE
PROCESS OF MEASURING THE OBSERVATIONS AND SAMPLES WAS INACCURATE.
THE CPK VALUE IS HIGHLY STANDARD DEVIATION DEPENDENT. THE MORE
NARROWER THE DEVIATION, THE HIGHER CPK WILL INCREASE.
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