y''' −2y' −4y = 0, y(0) = 6, y'(0) = 3, y''(0) = 22 solve the...

y''' −2y' −4y = 0, y(0) = 6, y'(0) = 3, y''(0) = 22

solve the initial value problem

You would convert it to m^3-2m-4=0. You find the root (m=2) and use synthetic division to find the other roots. m^2+2m+2 is what you get. I am stuck on what to do next?

y = 2e^(−x)*cosx−3e^(−x)*sinx + 4e^(2x) is the answer.

Expert Solution

Colby Messinger answered 1 month ago

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