Question : y'''+4y' =0 , y'''-2y''+4y'-8y=0 , y'''-3y''+3y'-y=0 , y^4 -4y'''+6y''-4y+y=0 , y^4+6y''+9y=0 , y^6+y'''=0

Expert Solution

milcah answered 2 years ago

Question : y''=4y'+8y=0 , (y''-4y'+13y)^2=0 , (y''+2y'+2y)^2=0 , y''-6y'+13y=0,y(0)=3 , y'(0)=13 , 2y''-6y'+17y=0,y(0)=2, y'(0)=13

ﬁnd the general solution of the given differential equation. 1. y''+2y'−3y=0 2. 6y''−y'−y=0 3. y''+5y' =0 4. y''−9y'+9y=0

3 Solve the following IVP a) y"+8y'-9y=0 y(1)=1, y'(1)=0 b)y"+4y'+5y=0 y(0)=1, y'(0)=0 c) y"-6y'+9y=0 y(0)=0, y'(0)=2...

3 Solve the following IVP a) y"+8y'-9y=0 y(1)=1, y'(1)=0 b)y"+4y'+5y=0 y(0)=1, y'(0)=0 c) y"-6y'+9y=0 y(0)=0, y'(0)=2 d)y"+4y'+4y=0 y(-1)=2, y'(-1)=1

1) x2y'' - 8xy' - 8y =0 2) y''- 3y' - 2y = 10sin(x)

Laplace Question : y''-3y'+2y=4cos2t,y(0)=-2,y'(0)=0

y''' −2y' −4y = 0, y(0) = 6, y'(0) = 3, y''(0) = 22 solve the...

y''' −2y' −4y = 0, y(0) = 6, y'(0) = 3, y''(0) = 22 solve the initial value problem You would convert it to m^3-2m-4=0. You find the root (m=2) and use synthetic division to find the other roots. m^2+2m+2 is what you get. I am stuck on what to do next? y = 2e^(−x)*cosx−3e^(−x)*sinx + 4e^(2x) is the answer.

Find the solution to the problem of initial value 2y'''' +3y'''--16''+15y'-- 4y=0 subjected to y(0)= --...

Find the solution to the problem of initial value 2y'''' +3y'''--16''+15y'-- 4y=0 subjected to y(0)= -- 2, y'(0)=6, y''(0)=3, y'''(0)=1/2

Give the Laplace transform of the solution to y"+2y'+3y=0 y(0)=-5 y'(0)=4

Find y as a function of x if y^(4)−6y′′′+9y′′=0, y(0)=7, y′(0)=11, y′′(0)=9, y′′′(0)=0.

Again considering y'' + 4y' + 3y = 0: (a) Solve the IVP y'' + 4y'...

Again considering y'' + 4y' + 3y = 0: (a) Solve the IVP y'' + 4y' + 3y = 0; y(0) = 1, y'(0) = α where α > 0. (b) Determine the coordinates (tm,ym) of the maximum point of the solution as a function of α. (c) Determine the behavior of tm and ym as α →∞.

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