solve using variation of parameters. y'' + 4y = 6 sint; y(0)=6, y'(0) = 0

Expert Solution

Colby Messinger answered 2 years ago

Solve y^4-4y"=g(t) using variation of parameters.

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y''' −2y' −4y = 0, y(0) = 6, y'(0) = 3, y''(0) = 22 solve the...

y''' −2y' −4y = 0, y(0) = 6, y'(0) = 3, y''(0) = 22 solve the initial value problem You would convert it to m^3-2m-4=0. You find the root (m=2) and use synthetic division to find the other roots. m^2+2m+2 is what you get. I am stuck on what to do next? y = 2e^(−x)*cosx−3e^(−x)*sinx + 4e^(2x) is the answer.

solve y'' + 4y =6 sin (t);y(0) =6, y'(0)=0 using 1st laplace transforms, 2nd undertinend coefficent,...

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Solve the initial value problem: y'' + 4y' + 4y = 0; y(0) = 1, y'(0)...

Solve the initial value problem: y'' + 4y' + 4y = 0; y(0) = 1, y'(0) = 0. Solve without the Laplace Transform, first, and then with the Laplace Transform.

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