y''' −2y' −4y = 0, y(0) = 6, y'(0) = 3, y''(0) = 22
solve the initial value problem
You would convert it to m^3-2m-4=0. You find the root (m=2) and
use synthetic division to find the other roots. m^2+2m+2 is what
you get. I am stuck on what to do next?
y = 2e^(−x)*cosx−3e^(−x)*sinx + 4e^(2x) is the answer.
1) Solve each of the following differential equations.
a)16y"-8y'+y=0
b) (d^4y)/(dx^4)-13((d^2y)/(dx^2))+36y=0
2) use Variation of Parameters to solve y"+16y=(1/3)csc4t
3) use undetermined coefficients to solve
y"-5y'+4y=3e^(3t)-5e^(2t) with y'(0)=-1 and y(0)=1
4) Explain why the product (A+B)(A-B) not equal A^2-B^2 fro two
NXN matrices A and B. what is the product of (A+B)(A-B)?