Question

I am working on routing path and subnet. The question is I am given with source 10.1.240.240 and the destinations is 10.2.240.240. How is the packet traveling?

Answer 1

Topology:

Given:

Source: 10.1.240.240

Destination: 10.2.240.240

The source and destination are both from class A. The class range is from 0 to 127 and all other address are from class B and class C.

Possible path can be selected from the given paths:

192.168.0.0/24

10.1.0.0/16

192.168.1.0/26

172.16.100.0/24

192.168.1.64/26

10.2.1.0/16

The source address is contained in the network 10.1.0.0/16

For the Network Address 10.1.0.0/16:

Hosts = (2^(32-16))-2 = 65534                   

Network:   10.1.0.0/16        

Broadcast: 10.1.255.255         

First usable address:   10.1.0.1          

Last usable address :   10.1.255.254       

So, the source address lies in the usable address range.

The destination address is contained in the network 10.2.1.0/16

For the Network Address 10.2.1.0/16:

Hosts/Net: (2^(16))-2 = 65534      

Network:   10.2.0.0/16           

Broadcast: 10.2.255.255          

First usable address:   10.2.0.1              

Last usable address :   10.2.255.254     

So, the destination address lies in the usable address range.    

Now as per the considered topology the possible path will be

Source Address -> Intermediate Address (Network)-> Destination Address      

10.1.0.0/16 -> 172.16.100.0/24 -> 10.2.1.0/16.

So, the path choosen will be from 10.1.0.0/16 -> 10.2.1.0/16.