Solve the equation below for y(t): y''+2y'-3y=8u(t-3): y(0) = 0; y'(0)=0

Solve the equation below for y(t):

y''+2y'-3y=8u(t-3): y(0) = 0; y'(0)=0

Expert Solution

Colby Messinger answered 2 years ago

Solve the differential equation by Laplace transform y^(,,) (t)-2y^' (t)-3y(t)=sint where y^' (0)=0 ,y=(0)=0

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