Solve the equation y'=5-8y with initial condition y'(0)=0

Expert Solution

milcah answered 2 years ago

Solve the differential equation. y'' − 8y' + 20y = te^t, y(0) = 0, y'(0) =...

Solve the differential equation. y'' − 8y' + 20y = te^t, y(0) = 0, y'(0) = 0 (Answer using fractions)

solve this equation y''-6y'+8y=1 when y(0)=1, y'(0)=7

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Solve the differential equation Y’(t) = AY(t), with initial condition Y(0) = [1;0] (a 2x1 matrix); where A = [ 9 , 5 ; -6 , -2 ]. Then, using Euler’s method with step size h=.1 over [ 0 , .5 ] fill in the table with header where the 2x1 matrix Yi is the approximation of the exact solution Y(ti) : t Yi Y(ti) ||Y(ti) – Yi ||

solve for the second order initial value problem= y"-6y+8y=0 y(0)=3, y'(0)=10

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y'' - 8y = 4, y(1) = 9, y'(0) = 5

Find the solution of the given initial value problem: y^(4)+2y′′′+y′′+8y′−12y=12sint+40e^−t y(0)=0, y′(0)=38/5, y′′(0)=4/5, y′′′(0)=−54/5

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solve the equation: y''-8y'+25y=5x3e-x - 7e-x

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