Question

In: Biology

You would like to sequence the genome of this organism. The restriction enzyme cut site for BglII is AGATCT.

 

A) You would like to sequence the genome of this organism. The restriction enzyme cut site for BglII is AGATCT. You will use it to clone fragments of the genome in order to sequence it. How many times would you expect this enzyme to cut within the chromosome of Andrebacillus wieczorius ? (2)

B) You decide to use a modified bacteriophage vector that can accommodate fragments digested with BglII. You use a partial digest on the chromosomal DNA. What are two reasons discussed in class that you need to use a partial digest in order to achieve your overall goal? (2)

C) Astonishingly, this is the first bacterium identified to generate a polyA tail on its transcripts! Wow! Considering that only 4% of the organisms’ genome codes for proteins, briefly describe how you would build a library of only the fractions of the genome that are rich in ORFs. In your answer, describe what type of a library this is called, the name of the technique,

Solutions

Expert Solution

A) The restriction enzyme, BglII has the restriction site of AGATCT where it cuts between A and G nucleotide phosphodiester bonds. The number of times this site is expected to cut within the chromosome of the organism will be dependent on the number of times this site is present in the chromosomes. And also not all the sites will be cut accurately by this enzyme as the DNA modifications will prevent it from cutting the chromosome sites accurately. Hence the number of times the enzyme will likely cut this DNA will be equal to the number of times this site is repeated in the chromosomal DNA.

B) Partial digestion is used in cloning. When you need to clone a DNA fragment that contains a specific restriction site also elsewhere than in the desired position (e.g. you need to use this enzyme to cut at the end of the fragment but not inside), you do partial digestion (you use a lower amount of the enzyme) and generate a mixture of fragments that have stochastically cleaved at these sites, just one site per DNA fragment. A subpopulation of this mixture contains the right DNA fragments with the internal restriction site intact and the site close to the end cleaved, and you use this fraction for cloning (for the other end of the fragment another enzyme is used, so you can do directional cloning). Hence the two reasons can be summarised as: partial digest generates stochastically cleaved sites which help in cloning and also they help to know the location of the restriction sites.

C)If a polyA tail is present then to clone these 4% of organisms genome that codes for proteins, we use a poly dT containing primers that automatically amplify these 4% DNA sequences and also help in generation of the clones. Such a library of clones generated by using poly dT primers is called as cDNA library as only coding regions of the DNA will be cloned.

 


Related Solutions

define the following terms: biotechnology, plasmid, selectalbe marker, multiple cloning site, restriction enzyme, restriction enzyme site,...
define the following terms: biotechnology, plasmid, selectalbe marker, multiple cloning site, restriction enzyme, restriction enzyme site, DNA transformation, annealing
You want to set-up a restriction enzyme digestion of a plasmidDNA sample. You would like...
You want to set-up a restriction enzyme digestion of a plasmid DNA sample. You would like to digest 0.75ug of this DNA with 50 units of BamHI and 50 units of HindIII in a total volume of 25uL containing 1x buffer A.How much (in uL) of the following stock solutions and water are needed?a) 200ng/uL plasmid DNAb) 10x buffer Ac) 50,000 units/mL BamHId) 25,000 units/mL HindIIIe) water
You digest a plasmid with a restriction enzyme that recognizes a single site on the plasmid....
You digest a plasmid with a restriction enzyme that recognizes a single site on the plasmid. When you perform gel electrophoresis on the digestion product, you quickly realize that there are two bands; one at the expected size and one near the well. Which of the following best explains the outcome? a.DNA was trapped in the agarose gel b.Some plasmids were not digested c.The presence of the chromosomal DNA d.The some plasmids ligated together
If a circular plasmid is cut one with a restriction enzyme what is the result? how...
If a circular plasmid is cut one with a restriction enzyme what is the result? how do we determine how many times a restriction enzyme cut.
What will you mix together in your restriction enzyme digest to cut out the gfp gene?
What will you mix together in your restriction enzyme digest to cut out the gfp gene?
1. The restriction enzyme SauIIIA recognizes the 4 bp sequence GATC, and the "6-cutter" enzyme BamHI...
1. The restriction enzyme SauIIIA recognizes the 4 bp sequence GATC, and the "6-cutter" enzyme BamHI recognizes the sequence GGATCC. Digestion of a particular bacteriophage genome produced a total of 160 SauIIIA fragments. Approximately how many BamHI fragments would you expect if: A) the phage genome has a “G+C” content of 50%? B) the phage genome is 80% G+C? 2. At least some of the RNA sequences below include significant regions that are self-complementary, and therefore might form secondary structures...
1. The restriction enzyme SauIIIA recognizes the 4 bp sequence GATC, and the "6-cutter" enzyme BamHI...
1. The restriction enzyme SauIIIA recognizes the 4 bp sequence GATC, and the "6-cutter" enzyme BamHI recognizes the sequence GGATCC. Digestion of a particular bacteriophage genome produced a total of 160 SauIIIA fragments. Approximately how many BamHI fragments would you expect if: A) the phage genome has a “G+C” content of 50%? B) the phage genome is 80% G+C? 2. At least some of the RNA sequences below include significant regions that are self-complementary, and therefore might form secondary structures...
The AseI restriction enzyme recognizes the sequence ATTAAT. Which of the following prokaryotic genomes will on...
The AseI restriction enzyme recognizes the sequence ATTAAT. Which of the following prokaryotic genomes will on average yield thelargest fragments after cutting with this enzyme? a. The AseI enzyme will not cut prokaryotic DNA b. S. aureus (G+C content = 34%) c. E. coli (G+C content = 50%) d. Rhodobacter sphearoides (G+C content = 68%) e. The G+C content does not affect fragment size when the recognition sequence has no G or C bases.
The restriction enzyme ApaI recognises and cleaves the sequence GGGCC^C (^ indicates where the DNA is...
The restriction enzyme ApaI recognises and cleaves the sequence GGGCC^C (^ indicates where the DNA is cleaved). You previously determined the size of the product amplified in the PCR. which is the region between the bold section TGGGCTAGGTGTAGGGGTCCTGAGTTCCGGGCTTTGCTACCCAGCTCTTGACTTCTGT TTCCCGATTTTA AATGAGCAGTTTGGACTAAGCCATTTTTAAGGAGAGCGATGGGGAGG GCTTCCCCCTTAGCACAAGGGCAGCCCTGGCCCTGGCTGAAGCCCAACCCCAACCTC CAAGACTGTGAGAGGATGGGGACTCATCCCTGGAGGAGGTGCCCCTCCTGGTATTGAT AAAGAATGCCCTGGGGAGGGGGCATCACAGGCTATTTGAACCAGCCCTGGGACCTTG GCCACCTCAGTGTCACTGGGTAGGGGGAACTCCTGGTCCCTTGGGTATATGGAAGGTA TCAGCAGAAAGCCAGCACTGGCAGGGACTCTTTGGTACAATACCCAGCATGCATGCTG TGCCAGGGGCTGACAAGGGTGCTGTCCTTGGCTTCCCCATTTTGGAGTGGTCACTTG CCTCTACTCCAGCCCCAGAAGTGGAAACTGAGATGATGTGTGGAGGAGAGAGCCAGC GTTCATGTTGGGAATCTTGAGGCTCCTTTCCAGCTCTCAGATTCTGTGATGCTCAAAGG GTGAGCTCTGTGGGCCCAGGACGCATGGTAGATGGAGCTTAGTCTTTCTGGTATCCAG CTGGGAGCCAAGCACAGAACACGCATCAGTGTTTATCAAATGACTGAGGAAATGAATGA ATGAATGTCTCCATCTCAACCCTCAGCCTGGTCCCTCCTTTTTTCCCTGCAGTTGGTAC AGATGGCATTGTCCCAGTCTGTTCCCTTCTCGGCCACAGAGCTTCTCCTGGCCTCTGC CATCTTCTGCCTGGTATTCTGGGTGCTCAAGGGTTTGAGGCCTCGGGTCCCCAAAGGC CTGAAAAGTCCACCAGAGCCATGGGGCTGGCCCTTGCTCGGGCATGTGCTGACCCTG GGGAAGAACCCGCACCTGGCACTGTCAAGGATGAGCCAGCGCTACGGGGACGTCCT GCAGATCCGCATTGGCTCCACGCCCGTGCTGGTGCTGAGCCGCCTGGACACCATCCG GCAGGCCCTG Now, identify the ApaI site within this region. If you digest the PCR product with ApaI, how many fragments of DNA would you...
The very useful restriction enzyme SpoBob hydrolyses the phosphodiester bond between the guanylates in the sequence...
The very useful restriction enzyme SpoBob hydrolyses the phosphodiester bond between the guanylates in the sequence AGGACCA. Is SpoBob generating blunt or sticky ends? Please explain.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT