Question

In: Statistics and Probability

A study compared the drug use of 288 randomly selected high school seniors exposed to a...

A study compared the drug use of 288 randomly selected high school seniors exposed to a drug education program (DARE) and 335 randomly selected high school seniors who were not exposed to such a program. Data for marijuana use are given in the accompanying table.

sample size number who use marijuana
exposed to DARE 288 137
not exposed to DARE 335 181



At the 5% significance level, is there convincing evidence that the proportion using marijuana is lower for students exposed to the DARE program?

Round these answers to two places after the decimal:
Test-statistic =   (to two places after the decimal)

P-value =   (to four places after the decimal)
There  --- is is not sufficient evidence to conclude that the proportion of students using marijuana is lower for students exposed to the DARE program.

Solutions

Expert Solution

Test-statistic = -1.61

P-value

Using the P-value approach: The p-value is p = 0.0537 and since p=0.0537 ≥ 0.05, it is concluded that the null hypothesis is not rejected.

There  is not sufficient evidence to conclude that the proportion of students using marijuana is lower for students exposed to the DARE program.


Related Solutions

An article compared the drug use of 288 randomly selected high school seniors exposed to a...
An article compared the drug use of 288 randomly selected high school seniors exposed to a drug education program (DARE) and 335 randomly selected high school seniors who were not exposed to such a program. Data for marijuana use are given in the accompanying table. n Number Who Use Marijuana Exposed to DARE 288 142 Not Exposed to DARE 335 177 Is there evidence that the proportion using marijuana is lower for students exposed to the DARE program? Use α...
The state test scores for 12 randomly selected high school seniors are shown on the right....
The state test scores for 12 randomly selected high school seniors are shown on the right. Complete parts​ (a) through​ (c) below. Assume the population is normally distributed. 1420 1220 982 695 720 837 724 750 542 627 1444 941 ​(a) Find the sample mean. x overbar x = ​(Round to one decimal place as​ needed.) ​(b) Find the sample standard deviation. s = ​(Round to one decimal place as​ needed.) ​(c) Construct a 90​% confidence interval for the population...
The state test scores for 12 randomly selected high school seniors are shown on the right....
The state test scores for 12 randomly selected high school seniors are shown on the right. Complete parts​ (a) through​ (c) below. Assume the population is normally distributed. 12 scores- 1430 1220 985 694 729 837 724 750 544 621 1443 949 1) find the sample mean 2) find the standard deviation 3) construct a 90% confidence interval for the population mean
The state test scores for 12 randomly selected high school seniors are shown on the right....
The state test scores for 12 randomly selected high school seniors are shown on the right. Complete parts​ (a) through​ (c) below. Assume the population is normally distributed. 1420 1225 988 691 730 833 721 748 550 628 1445 946 ​(a) Find the sample mean. (b) find the standard deviation (c) construct 90% confidence interval.
10) The SAT scores for 12 randomly selected seniors at a particular high school are given...
10) The SAT scores for 12 randomly selected seniors at a particular high school are given below. Assume that the SAT scores for seniors at this high school are normally distributed. 1,271 1,288 1,278 616 1,072 944 1,048 968 931 990 891 849 a) Find a 95% confidence interval for the true mean SAT score for students at this high school. b) Provide the right endpoint of the interval as your answer. Round your answer to the nearest whole number.
2. Suppose a randomly chosen group of 150 high school juniors and seniors who took the...
2. Suppose a randomly chosen group of 150 high school juniors and seniors who took the SAT twice over a period of six months showed an average improvement on the second SAT of 25 points. The standard deviation of the difference in the scores between the first and second SAT was 20 points. a. What is the appropriate design for this situation? b. Set up an appropriate hypotheses to test the claim that the score on the second SAT is,...
There are 723 seniors at a large high school. (a) Explain how you would use a...
There are 723 seniors at a large high school. (a) Explain how you would use a random number table to select a random sample of 30 seniors. Explain your method clearly! I should be able to hand you directions to Mr. Carter and he should be able to select the sample. (b) Using the random digits below, select the first five seniors using your method from Part (a). 73190 32533 04470 29669 84407 90785 65956 86382 95857 07118 87664 92099...
The SAT scores of 20 randomly selected high school students has a mean of =1,185 and...
The SAT scores of 20 randomly selected high school students has a mean of =1,185 and a sample standard deviation s=168.0. Construct an 98% confidence interval for the true population mean and interpret this interval
The SAT scores of 20 randomly selected high school students has a mean of =1,185 and...
The SAT scores of 20 randomly selected high school students has a mean of =1,185 and a sample standard deviation s=168.0. Construct an 98% confidence interval for the true population mean and interpret this interval
1.) What is the probability that a randomly selected female student had a high school GPA...
1.) What is the probability that a randomly selected female student had a high school GPA lower than 3.75? Solve this problem using the Standard Normal Table (Z table). Show all work and provide the probability as a decimal rounded to four decimal places. 2.) ​​​​​​​If a female student had a high school GPA of 4.00, what percentile would this be for all female students? Solve this problem using the Standard Normal Table (Z table). Show all work and provide...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT