Question
In: Statistics and Probability
The SAT scores of 20 randomly selected high school students has a mean of =1,185 and...
The SAT scores of 20 randomly selected high school students has a mean of =1,185 and a sample standard deviation s=168.0. Construct an 98% confidence interval for the true population mean and interpret this interval
Solutions
Expert Solution
Solution :
Given that,
= 1185
s = 168.0
n = 20
Degrees of freedom = df = n - 1 = 20- 1 = 19
At 98% confidence level the t is ,
= 1 - 98% = 1 - 0.98 = 0.02
/
2 = 0.02 / 2 = 0.01
t
/2,df = t0.01,19 =2.539
Margin of error = E = t/2,df
* (s /
= 2.539 * (168.0 /
The 98% confidence interval estimate of the population mean is,
- E < 
<
+ E
1185 - 97.8577 <
< 1185+ 97.8577
1087.1423 <
< 1282.8577
(1087.1423 , 1282.8577 )
orchestra answered 2 years agoRelated Solutions
The SAT scores of 20 randomly selected high school students has a mean of =1,185 and...
The SAT scores of 20 randomly selected high school students has
a mean of =1,185 and a sample standard deviation s=168.0. Construct
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interpret this interval
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10)
The SAT scores for 12 randomly selected seniors at a particular
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1,271
1,288
1,278
616
1,072
944
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931
990
891
849
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