Question

In: Biology

In cocker spaniels, solid coat color is dominant (S) over spotted coat (s). Suppose a true-breeding...

In cocker spaniels, solid coat color is dominant (S) over spotted coat (s). Suppose a true-breeding solid-colored dog is crossed with a spotted dog, and the F1 dogs are interbred.

What is the probability that the first puppy born will have a solid coat?

What is the probability that the solid-coated puppy in the previous question is homozygous for the solid coat allele?

What is the probability that if four puppies are born, all of them will have a spotted coat?

What is the probability that if six puppies are born, 2 of them would have a spotted coat and 4 of them would have a solid coat? Please round your answer to the nearest hundredth or leave as a fraction.

The following two individuals are crossed: Aa Bb Cc Dd x Aa bb Cc Dd What proportion of the progeny will have the following genotype? Express as either a fraction or as a decimal] Aa Bb CC dd p=

What is the probability that one of the progeny will have all dominant OR all recessive phenotype? p=

Expert Solution

Solid colored dog= SS

Spotted dog= ss

F1= Ss

When F1 is interbred, Ss X Ss

We get, SS(solid]), Ss(solid), Ss(solid), ss(spotted)

1)The probability of firstborn puppy will have solid coat is 3/4 or 0.75. As the solid coat is dominant, the heterozygous genotype will also show a solid phenotype.

2) The probability of the solid-coated puppy in the previous question is homozygous for the solid coat allele is 1/2 or 0.5

3) The probability that if four puppies are born, all of them will have a spotted coat is 1/256 or 0.0039

As the probability of a puppy having a spotted coat is 1/4. so if four puppies are born, then probability of all of them having spotted coat becomes 1/4 X 1/4 X 1/4 X 1/4

4) The probability that if six puppies are born, 2 of them would have a spotted coat and 4 of them would have a solid coat is 81/4096 or 0.019

As the probability of a puppy having a solid coat is 3/4. so if four puppies are born, then the probability of them having spotted coat becomes 3/4 X 3/4 X 3/4 X 3/4

As the probability of a puppy having a spotted coat is 1/4. so if two puppies are born, then the probability of them having spotted coat becomes 1/4 X 1/4.

Probability of six puppies, where 2 of them would have a spotted coat and 4 of them would have a solid coat becomes 3/4 X 3/4 X 3/4 X 3/4 X 1/4 X 1/4 = 81/4096

5) Aa Bb Cc Dd x Aa bb Cc Dd

To calculate the probability of genotype. perform a monohybrid cross of each gamete and then write the probability of gamete according to the monohybrid cross to find out the probability of genotype asked.

the first monohybrid cross, Aa X Aa = AA Aa Aa aa. So the probability of Aa becomes 1/2

the second monohybrid cross, Bb X bb= Bb Bb bb bb. So the probability of Bb becomes 1/2

the third monohybrid cross, Cc X Cc= CC Cc Cc cc. So the probability of CC becomes 1/4

the fourth monohybrid cross, Dd X Dd= DD Dd Dd dd. So the probability of dd becomes 1/4

the probability of Aa Bb CC dd genotype = 1/2 X 1/2 X 1/4 X 1/4 = 1/64

the first monohybrid cross, Aa X Aa = AA Aa Aa aa. So the probability of aa becomes 1/4

the second monohybrid cross, Bb X bb= Bb Bb bb bb. So the probability of bb becomes 1/2

the third monohybrid cross, Cc X Cc= CC Cc Cc cc. So the probability of cc becomes 1/4

the fourth monohybrid cross, Dd X Dd= DD Dd Dd dd. So the probability of dd becomes 1/4

Probability of all recessive phenotype aa bb cc dd = 1/4 X 1/2 X 1/4 X 1/4 = 1/128

gladiator answered 8 months ago

In dogs, solid coat color (S ) is dominant over white spotted coat (s ). In...

In dogs, solid coat color (S ) is dominant over white spotted coat (s ). In a cross between two heterozygous dogs, what would be the probability of having a first litter of six pups, the firstborn with spotted fur, and then among the next five, three with solid fur and two with spotted fur; and then a second litter of seven pups in which the firstborn is spotted, the second born is solid, and then the remaining five pups...

In cocker spaniels, solid coat color is dominant over spotted coat color. If two heterozygous dogs...

In cocker spaniels, solid coat color is dominant over spotted coat color. If two heterozygous dogs were crossed to each other, what would be the probability of the following combinations of offspring? a. A litter of eight pups, two with solid fur and six with spotted fur. b. A first litter of six pups, four with solid fur and two with spotted fur, and then a second litter of five pups, all with solid fur. c. A first litter of...

In Triskelian cats, in the Blondish Galaxy, black coat color is dominant over grey. Coat color...

In Triskelian cats, in the Blondish Galaxy, black coat color is dominant over grey. Coat color is determined by a single autosomal gene with two alleles: B = black coat color; b = grey coat color. The autosomal gene for eye color is hypothesized to assort independently from the gene for coat color. The two alleles are: R = green eye color; r = blue eye color. If a green-eyed black female cat whose mother has a grey coat and...

In guinea pigs, black coat color is dominant over white, short hair is dominant over long,...

In guinea pigs, black coat color is dominant over white, short hair is dominant over long, and rough coat is dominant over smooth. Show the Punnett Square for a cross between a homozygous black, short-haired, rough coat guinea pig and a homozygous white, long-haired, smooth coat guinea pig. What do the offspring look like?

In dogs, the allele for black coat color (B) is dominant to the allele for brown...

In dogs, the allele for black coat color (B) is dominant to the allele for brown coat color (b). But if a dog has two copies of the recessive allele for a pigment-depositing gene (e), it can only have yellow coat color. In a cross of two doubly heterozygous black dogs (BbEe x BbEe), what fraction of the next generation would we expect to be yellow? WHY? a.1/8 b.1/4 c.2/3 d.3/16

In mice the allele for black coat color (B) is dominant to the allele for white...

In mice the allele for black coat color (B) is dominant to the allele for white coat color (b). The allele for long tail (T) is dominant to the allele for short tail (t). For the same cross: BbTt x bbTt a. Using the Probability Method illustrated in lecture, break the complex two-gene cross into two simple single-gene crosses (note that the Probability Method can be used if it is known that the alleles of the different genes Assort...

In horses, black coat (B) is dominant over brown coat (b), and being a trotter (T)...

In horses, black coat (B) is dominant over brown coat (b), and being a trotter (T) is dominant over being a pacer (t). A heterozygous black coat, trotter male and a heterozygous black coat, trotter female are crossed. Complete the Punnett Square and determine the phenotypes of their potential offspring. Phenotypes: _________________________________________________ In pea plants, the gene for round seed (R) is dominant, and wrinkled seeds (r) are recessive. The endosperm of the pea is also either starchy, a dominant...

Dark fur is dominant in pocket mice. A true breeding dark fur mouse is mated with...

Dark fur is dominant in pocket mice. A true breeding dark fur mouse is mated with a true breeding light fur mouse. Their F1 offspring are mated with each other. (a) What is the probability that the first three F2 offspring have dark fur? (b) What is the probability that three out of five offspring will have dark fur? (c) The phenotypes for 50 F2 mice are 30 dark and 20 light. You want to test the goodness of fit...

In cucumbers, orange fruit color (R) is dominant over cream fruit color (r). A cucumber plant...

In cucumbers, orange fruit color (R) is dominant over cream fruit color (r). A cucumber plant homozygous for orange fruit is crossed with a plant homozygous for cream fruit. The F1 are intercrossed to produce the F2. Give the genotypes and phenotypes of the parents, the F1, and the F2. Give the genotypes and phenotypes of the offspring of a backcross between the F1 and the orange-fruited parent. Give the genotypes and phenotypes of a backcross between the F1 and...

Full color in domestic cats is dominant over dilute color. Of 600 cats observed, 200 have...

Full color in domestic cats is dominant over dilute color. Of 600 cats observed, 200 have dilute color. If this population is in Hardy-Weinberg equilibrium, what is the frequency of the dilute allele? How many of the 400 cats with full color are likely to be heterozygous?