In guinea pigs, black coat color is dominant over white, short hair is dominant over long,...

In guinea pigs, black coat color is dominant over white, short hair is dominant over long, and rough coat is dominant over smooth. Show the Punnett Square for a cross between a homozygous black, short-haired, rough coat guinea pig and a homozygous white, long-haired, smooth coat guinea pig. What do the offspring look like?

Expert Solution

Black coat is dominant over white coat. Let assume, B allele is responsible for black coat and b allele is responsible for white coat . Homozygous BB allele and heterozygous Bb allele will express black coat and only homozygous bb allele will express white coat.

Short hair ( let assume S allele is responsible for short hair) is dominant over long hair ( s allele is responsible for long hair) therefore homozygous SS allele and heterozygous Ss allele will express short hair trait, and only homozygous ss allele is responsible for long hair

Rough coat ( let assume R allele is responsible for rough coat) is dominant over smooth coat ( r allele is responsible for smooth coat) therefore homozygous RR and heterozygous Rr allele can express rough coat trait and only homozygous rr allele can express smooth coat .

Here a cross occurs between homozygous black coat (BB), short hair (SS ), rough coat (RR) [ gamets will be B, S, R] and homozygous white coat ( bb) long hair ( ss ) and smooth coat ( rr) [ gamets will be b, s, r] therefore the cross is - BB SS RR × bb ss rr

F₁	b s r ( gamets from white smooth coated with long hair)
B S R ( gamets from black rough coated with small hair	Bb Ss Rr

All the offspring of F₁ generation looks like black, rough coated with small hair ( as black and rough coat and small hair is dominant) and all the F₁ offspring will be heterozygous Bb Ss Rr

gladiator answered 3 months ago

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