In: Statistics and Probability
The table below includes results from polygraph? (lie detector) experiments conducted by researchers. In each? case, it was known if the subjected lied or did not? lie, so the table indicates when the polygraph test was correct. Use a 0.05 significance level to test the claim that whether a subject lies is independent of the polygraph test indication. Do the results suggest that polygraphs are effective in distinguishing between truth and? lies? State the null and alternate hypothesis, test statistic, p-value and conclusion.
_ | Did_Not_Lie | Lied |
Polygraph_indicated_lie | 15 | 50 |
Polygraph_indicated_no_lie | 21 | 12 |
Claim: polygraphs are effective in distinguishing between truth and? lies
The null and alternative hypothesis is
H0: polygraphs are not effective in distinguishing between truth and? lies.
H1: polygraphs are effective in distinguishing between truth and? lies.
Level of significance = 0.05
Test statistic is
O: Observed frequency
E: Expected frequency.
E = ( Row total* Column total) / Grand total
Did Not lie | Lied | Total | |
Polygraph indicated lie | 15 | 50 | 65 |
Polygraph indicated no lie | 21 | 12 | 33 |
Total | 36 | 62 | 98 |
O | E | (O-E) | (O-E)^2 | (O-E)^2/E |
15 | 23.87755 | -8.87755 | 78.81091 | 3.300627943 |
50 | 41.12245 | 8.877551 | 78.81091 | 1.916493645 |
21 | 12.12245 | 8.877551 | 78.81091 | 6.501236858 |
12 | 20.87755 | -8.87755 | 78.81091 | 3.774911724 |
Total | 15.493 |
Degrees of freedom = (r-1)*(c-1) = (2-1)*(2-1) = 1*1 = 1
P-value = P() = 0.000083
P-value < 0.05 we reject null hypothesis.
Conclusion:
polygraphs are effective in distinguishing between truth and? lies.