Question

Write a Python program in a file called consonants.py, to solve the following problem using a nested loop. For each input word, replace each consonant in the word with a question mark (?). Your program should print the original word and a count of the number of consonants replaced. Assume that the number of words to be processed is not known, hence a sentinel value (maybe "zzz") should be used. Sample input/output:

Please enter a word or zzz to quit: Dramatics

The original word is: dramatics

The word without consonants is: ??a?a?i??

The number of consonants in the word are: 6

Please enter another word or zzz to quit: latchstring

The original word is: latchstring

The word without consonants is: ?a??????i??

The number of consonants in the word are: 9

Please enter another word or zzz to quit: YELLOW

The original word is: yellow

The word without consonants is: ?e??o?

The number of consonants in the word are: 4

Please enter another word or zzz to quit: zZz

Answer 1

Below is the code you will be needing  Let me know if you have any doubts or if you need anything to change.

Thank You !!

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while True:
    word = input('Please enter a word or zzz to quit: ').lower()
    if word == 'zzz':
        break
    else:
        count = 0
        modified = ''
        for letter in word:
            found = False
            for consonant in 'bcdfghjklmnpqrstvwxyz':
                if letter == consonant:
                    modified += '?'
                    count += 1
                    found = True
                    break
            if found is not True:
                modified += letter
        print('The original word is: {}'.format(word))
        print('The word without consonants is: {}'.format(modified))
        print('The number of consonants in the word are: {}'.format(count))