Question

In: Biology

A pea plant that is heterozygous for both flower colour and stamen length is crossed with...

A pea plant that is heterozygous for both flower colour and stamen length is crossed with a pea plant that is homozygous recessive for both. Of the offspring, 89 have red flowers and long stamens, 98 have white flowers and short stamens, 10 have red flowers and short stamens and 9 have white flowers and long stamens. What is the map distance between these two loci?

A) Cannot be calculated because the two loci are on different chromosomes

B) 9.2 cM

C) 4.9 cM

D) 9.2 %

Solutions

Expert Solution

recombination frequency between genes in percentage is the distance between genes in map units.

The maximum possible recombination frequency is 50% then the genes are not linked if the genes are linked the recombination frequency is less than 50%.

recombination frequency= ( number of recombinant progenies/total number of progenies) 100

recombination frequency is the percentage of recombinant progenies, so if the genes are linked the number of recombinant progenies are less than the parental type progenies.

among offspring 89 have red flowers and long stamens, 98 have white flowers and short stamens, 10 have red flowers and short stamens and 9 have white flowers and long stamens.

red flowers and short stamens and white flowers and long stamens are recombinant progenies.

recombination frequency= ((10+9)/(10+9+98+89)) 100

=9.2 %

so the distance between the genes is 9.2 cM

B) 9.2 cM

gladiator answered 1 week ago
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