In: Biology
Assume that a cross is made between a heterozygous tall pea plant and a homozygous short pea plant. Fifty offspring are produced in the following frequency: 30 = tall 20 = short
(a) What frequency of tall and short plants is expected?
(b) To test the goodness of fit between the observed and expected values, provide the needed statement of the null hypothesis.
(c) Compute a Chi-square value associated with the appropriate test of significance.
(d) How many degrees of freedom are associated with this test of significance?
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(observed-expected)squared/expected = Chi-squared
So if the expected ratio is 1:1 than the expected tall is 25 and the expected short is 25.
Therefore the calculated Chi-squared value is 1 for tall and 1 for short and the toal calculated Chi-squared is 2.
We can also understand this answer as the following calculation that….
a cross is made between a heterozygous tall pea plant and a homozygous short pea plant.
Fifty offspring are produced in the following frequency:
30 = tall
20 = short
(a) What frequency of tall and short plants is expected?
(a) 1:1 (25 tall and 25 short)
(b) To test the goodness of fit between the observed and expected values, provide the needed stateme (b) The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance. nt of the null hypothesis.
(c) Compute a Chi-square value associated with the appropriate test of significance.
(c) χ2 = 2
(d) How many degrees of freedom are associated with this test of significance?
(d) 1