Question

In: Math

Two pea plants are crossed. Both are heterozygous for purple blossom color, while one is homozygous...

Two pea plants are crossed. Both are heterozygous for purple blossom color, while one is homozygous for being short and the other is heterozygous for being tall. In pea plants, tall is dominant to short, and purple flowers are dominant to white.

Fill out the table below for the probability of each possible phenotype. Report probability as a decimal rounded to four places (e.g. 0.1250, not 1/8 or 12.5%).

Phenotype Probability
tall purple
short purple
tall white
short white

In a population of 150 pea plants, there are 53 tall-purple plants, 52 short-purple plants, 22 tall-white plants, and 23 short-white plants. In order to test if the two traits are experiencing independent assortment researchers would perform a chi squared test. The (null/alternative)  hypothesis states that the two genes are independently assorted while the (null/alternative)  hypothesis states the two genes are dependent.

What is your calculated Chi Squared statistic?

  • When performing a contingency table, do not round your expected values!!
  • Report your calculated X2 rounded to four decimal places

What is the corresponding P value?

  • Use the formula =1-(CHISQ.DIST(X2,df,TRUE)) to convert calculated X2 into a P value
  • Report your answer rounded to 4 decimal places

Do you fail to reject or reject the null hypothesis?

As a result of this statistical analysis, it is possible to conclude that pea plant height and pea plant blossom color (are or are not)  linked traits.

Solutions

Expert Solution

TS = 0.032
p-value = 0.8536
we fail to reject the null
As a result of this statistical analysis, it is possible to conclude
that pea plant height and pea plant blossom color (are not) linked traits.


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