In: Math
Two pea plants are crossed. Both are heterozygous for purple blossom color, while one is homozygous for being short and the other is heterozygous for being tall. In pea plants, tall is dominant to short, and purple flowers are dominant to white.
Fill out the table below for the probability of each possible phenotype. Report probability as a decimal rounded to four places (e.g. 0.1250, not 1/8 or 12.5%).
Phenotype | Probability |
tall purple | |
short purple | |
tall white | |
short white |
In a population of 150 pea plants, there are 53 tall-purple plants, 52 short-purple plants, 22 tall-white plants, and 23 short-white plants. In order to test if the two traits are experiencing independent assortment researchers would perform a chi squared test. The (null/alternative) hypothesis states that the two genes are independently assorted while the (null/alternative) hypothesis states the two genes are dependent.
What is your calculated Chi Squared statistic?
What is the corresponding P value?
Do you fail to reject or reject the null hypothesis?
As a result of this statistical analysis, it is possible to conclude that pea plant height and pea plant blossom color (are or are not) linked traits.
TS = 0.032
p-value = 0.8536
we fail to reject the null
As a result of this statistical analysis, it is possible to
conclude
that pea plant height and pea plant blossom color (are
not) linked traits.