Question

In: Biology

In tomatoes, a heterozygous plant with normal fruit and purple stems is crossed with a recessive...

In tomatoes, a heterozygous plant with normal fruit and purple stems is crossed with a recessive plant having fasciated fruit and green stems. The following distribution of offspring is observed:
normal fruit, purple stems 38.5%  fasciated fruit, green stems 38.5%
normal fruit, green stems 11.5%
  fasciated fruit, purple stems 11.5%
What conclusion can be made regarding the loci for fruit shape and stem color? HINT determine the RF

What the loci and RF here mean? How to answer this question?

Solutions

Expert Solution

Let the genotype of the heterozygous tomato plant with normal fruit and purple stems be represented as FfSs.
Let the genotype of the recessive tomato plant with fasciated fruit and green stems be represented as ffss.
Upon crossing, as per Mendelian Laws, we should observe either FS or fs gamete from the heterozygous plant and only fs gamete from the recessive one.
As such the progeny should be 50% normal fruit, purple stems & 50% fasciated fruit, green stems.
Production of the intermediate varieties, that is normal fruit, green stems & fasciated fruit, purple stems, concludes that the loci for fruit shape and stem colour on the same side of the centromere and are as such, undergoing recombination at a synapse in between the two loci to yield alternating allele combinations not seen in parent heterozygous plant.
The Recombination is causing the RF and rf gametes from the heterozygous plant to undergo genetic crossing over and also yield the Rf and rF gametes, although not at equal frequency. Hence Recombination Frequency is calculated as = (Number of Recombinants) / (Total Number of Offsprings)
= (11.5% + 11.5%) / (100%)
= 23% RF ANSWER


Related Solutions

The model plant neitzelweed (Bogus testplantii) normally has large, blue fruit and spiny stems. Recessive mutants...
The model plant neitzelweed (Bogus testplantii) normally has large, blue fruit and spiny stems. Recessive mutants have been found with white, small fruits and spineless stems. A pure breeding wild type plant is crossed with a pure breeding white, small, spineless plant. All of the F1 are wild type phenotype. When the F1 is crossed with the homozygous recessive parent the progeny types and numbers below are observed. Create a genetic map showing the relationship and distances between the genes...
homozygous recessive is crossed with a heterozygote, what percent chance is there of getting a heterozygous...
homozygous recessive is crossed with a heterozygote, what percent chance is there of getting a heterozygous genotype in f1?
Two pea plants are crossed. Both are heterozygous for purple blossom color, while one is homozygous...
Two pea plants are crossed. Both are heterozygous for purple blossom color, while one is homozygous for being short and the other is heterozygous for being tall. In pea plants, tall is dominant to short, and purple flowers are dominant to white. Fill out the table below for the probability of each possible phenotype. Report probability as a decimal rounded to four places (e.g. 0.1250, not 1/8 or 12.5%). Phenotype Probability tall purple short purple tall white short white In...
12. If a heterozygous dominant tall pea is crossed with a short plant, what is the...
12. If a heterozygous dominant tall pea is crossed with a short plant, what is the expected phenotype ratio? 13. Give three examples of phenotypes. 14. Why is skin color classified as polygenic inheritance? 15. If the parental genotype is EeWw, what are the potential allele combinations that could occur at the end of meiosis? 16. During DNA replication, a DNA strand with the bases CTAGGT will produce what complimentary strand of bases? 17. In their experiment, what would Hershey...
Drosophila females heterozygous for three recessive mutations, a, b, and c were crossed to males homozygous...
Drosophila females heterozygous for three recessive mutations, a, b, and c were crossed to males homozygous for all three mutations. The cross yielded the following results. Phenotype Number A B C - 75 A B c - 348 A b c - 96 a B C - 110 a b C - 306 a b c - 65 Determine the gene order. Determine the distance between genes . Make a genetic map of the genes.
In violets, purple is dominant to white and tall stems are dominant to short stems. ....
In violets, purple is dominant to white and tall stems are dominant to short stems. . A tall purple plant that is heterozygous at both loci is crossed with a double homozygous recessive plant. What is the probability of obtaining either a tall white plant or a short purple plant? What percent of the offspring are expected to be heterozygous at one or both loci? What will be the expected ratio of the F2 offspring of the F1 generation?
Black body (b) and purple eye (pr) are recessive autosomal mutations in Drosophila. Bridges crossed b/b...
Black body (b) and purple eye (pr) are recessive autosomal mutations in Drosophila. Bridges crossed b/b females and pr/pr males. F2 cross produced 684 wild-type, 371 black-bodied, and 300 purple-eyes flies. Do these result indicate that the b and pr genes are closely linked? Explain. Remember that there is no crossing over in male Drosophila
A purple flowering, smooth seed dihybrid plant (genotype PpSs) is test crossed with a white flowering,...
A purple flowering, smooth seed dihybrid plant (genotype PpSs) is test crossed with a white flowering, wrinkled seed plant (genotype ppss). These produce progeny in the following numbers of four phenotypes: 24:76:74:26 (purple flower + smooth seed coat: purple flower + wrinkled seed coat: white flower + smooth seed coat: white flower + wrinkled seed coat). a) Explain how ratios of progeny show that the two genes are linked. b) How many map units separate the colour and seed coat...
1)A homozygous tomato plant with red fruit and yellow flowers was crossed with a homozygous tomato...
1)A homozygous tomato plant with red fruit and yellow flowers was crossed with a homozygous tomato plant with golden fruit and white flowers. The F1 all had red fruit and yellow flowers. The F1 were testcrossed by crossing them to homozygous recessive individuals, and the following offspring were obtained: Red fruit and yellow flowers41 Red fruit and white flowers7 Golden fruit and yellow flowers8 Golden fruit and white flowers44 How many map units separate these genes? A)17.6 B)17.1 C)15 D)18.1...
Generate a Punnett square for a heterozygous individual crossed with a heterozygous individual. Make the mutation...
Generate a Punnett square for a heterozygous individual crossed with a heterozygous individual. Make the mutation recessive. What percentage of the offspring contain the mutation?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT