Question

Create a 32-bit Linux-based assembler language program (nasm) which:

1. Defines these variables:

A: A single byte

B: A word

C: A double word

D: A double word

2. Using the eax register (and its sub-registers), process the following equations (ONLY using the mov, add and sub assembly keywords):

I. A + (B + C) = D

II. (A + C) - B = D

3. Using the linux function library, print a string describing each equation, then values in each variable, and then the answer in the resulting variable

4.Use the following values in your equation:

I. 10h

II. 2000h

III. 30000

Sample Output: The Result of A + (B + C) = D is: 32010

When printing out a string in NASM, use the linux function library call PrintString. Make sure your string is 00h terminated. • When printing out a Hexadecimal value in NASM, use the linux function library call Print32bitNumHex

Answer 1

section .data
   msg db "The Result of A + (B + C) = D is :%d",10,0
   msg1 db "The Result of (A + C)-B = D is :%d",0

    A dd 10
    B dd 2000
    C dd 30000
section .bss
    D resd 1
section .text
   global main
   extern printf
main:
    
        ;A+(B+C)=D
   mov eax,dword[B]
   add eax,dword[C]
   add eax,dword[A]
   mov dword[D],eax
  
   push eax
   push msg
   call printf
   add esp,8
  
  
   mov eax,dword[A]
   add eax,dword[C]
   sub eax,dword[B]
   mov dword[D],eax
   push eax
   push msg1
   call printf
   add esp,8