Question

In: Statistics and Probability

Question 1: A businesswoman is considering whether to open a coffee shop in a local shopping...

Question 1:

A businesswoman is considering whether to open a coffee shop in a local shopping center. Before making this decision, she wants to know how much money people spend per week at coffee shops in that area. She took a random sample of 26 customers from the area who visit coffee shops and asked them to record the amount of money (in dollars) they would spend during the next week at coffee shops. At the end of the week, she obtained the following data (in dollars) from these 26 customers:

16.60 39.03 15.17 14.38 5.07 63.68 10.20 13.19 32.27
36.15 16.16 66.08 10.31 37.11 3.15 6.89 34.58 6.38
36.43 27.66 38.56 13.30 9.70 9.34 1.19 5.35

Assume that the distribution of weekly expenditures at coffee shops by all customers who visit coffee shops in this area is approximately normal.



Round your answers to cents.

a. What is the point estimate of the corresponding population mean?

x ¯ = $Enter your answer; point estimate

b. Make a 98 % confidence interval for the average amount of money spent per week at coffee shops by all customers who visit coffee shops in this area.

Question 2:A sample selected from a population gave a sample proportion equal to 0.61 .

Round your answers to three decimal places.

a. Make a 98 % confidence interval for p assuming n = 75 .

( Enter your answer; confidence interval assuming n=75, lower bound ,Enter your answer; confidence interval assuming n=75, upper bound  )

b. Construct a 98 % confidence interval for p assuming n = 625 .

( Enter your answer; confidence interval assuming n=625, lower bound ,Enter your answer; confidence interval assuming n=625, upper bound  )

c. Make a 98 % confidence interval for p assuming n = 1375 .

Question 3:According to a Pew Research Center nationwide telephone survey of adults conducted March 15 to April 24, 2011, 69 % of college graduates said that their college education gave them maturity (Time, May 30, 2011). Suppose that this survey included n = 1340 college graduates.

a. What is the point estimate of the corresponding population proportion?

p ^ = Enter your answer; point estimate

b. Construct a 99 % confidence interval for the proportion of all college graduates who will say that their college education gave them maturity. What is the margin of error for this estimate?

Round your answers to three decimal places.

The confidence interval is Enter your answer; confidence interval, lower bound to Enter your answer; confidence interval, upper bound .


The margin of error is E =

Question 4:

It is said that happy and healthy workers are efficient and productive. A company that manufactures exercising machines wanted to know the percentage of large companies that provide on-site health club facilities. A sample of 240 such companies showed that 99 of them provide such facilities on site.

Construct a 90 % confidence interval for the percentage of all such companies that provide such facilities on site. What is the margin of error for this estimate?

Round your answers to one decimal place.

Confidence interval: Enter your answer; confidence interval, lower bound % to Enter your answer; confidence interval, upper bound %

Margin of error: Enter your answer; Margin of error

Solutions

Expert Solution

a. Let X: the money spent at coffee shop

b. I have given my best to solve your problem. Please like the answer if you are satisfied with it. ?


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