A plane electromagnetic wave with magnetic field amplitude 0.02 T is propagating through a vacuum. What...

A plane electromagnetic wave with magnetic field amplitude 0.02 T is propagating through a vacuum.

What is the electric field amplitude? B) What is the magnitude of the Poynting vector?

C. If the wavelength is 500 nm what is the wave frequency and the energy of a single photon?

D. How many of these photons must pass through a square meter each second to yield the power flux calculated in part B?

Solutions

Expert Solution

The magnetic field amplitude is given by

A)
The electric field amplitude is



B)
The magnitude of the Poynting vector is





C)
Given the wavelength

the wave frequency is


And so, the energy of the single photon is



D)
  So, the number of photons moving per second per square meter to yield the power flux calculated in part B, is given by

genius_generous answered 2 hours ago

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