A parallel-plate capacitor with plate separation of 1.0 cm has square plates, each with an area...

A parallel-plate capacitor with plate separation of 1.0 cm has square plates, each with an area of 6.0 × 10 -2 m 2. What is the capacitance of this capacitor if a dielectric material with a dielectric constant of 2.4 is placed between the plates, completely filling them? ( ε 0 = 8.85 × 10 -12 C 2/N ∙ m 2)

A)1.3 × 10-12 F

B)1.3 × 10-10 F

C)64 × 10-14 F

D)15 × 10-12 F

E)15 × 10-14 F

Expert Solution

Consider the parallel plate at distance d and area A then we know electric field for a plate is given by,

E=surface charge density/2*£

The two plates have opposite charge. So the electric field will be added to each other..

genius_generous answered 2 months ago

A parallel-plate capacitor has plates of area 0.15 m2 and a separation of 1.00 cm. A...

A parallel-plate capacitor has plates of area 0.15 m2 and a separation of 1.00 cm. A battery charges the plates to a potential difference of 100 V and is then disconnected. A dielectric slab of thickness 4 mm and dielectric constant 4.8 is then placed symmetrically between the plates. (a) What is the capacitance before the slab is inserted? pF (b) What is the capacitance with the slab in place? pF (c) What is the free charge q before the...

A parallel-plate capacitor has square plates that are 8.20 cm on each side and 4.80 mm...

A parallel-plate capacitor has square plates that are 8.20 cm on each side and 4.80 mm apart. The space between the plates is completely filled with two square slabs of dielectric, each 8.20 cm on a side and 2.40 mm thick. One slab is Pyrex glass and the other slab is polystyrene. If the potential difference between the plates is 88.0 V, find how much electrical energy (in nJ) can be stored in this capacitor.

A parallel plate, air filled capacitor, has plates of area 0.82 m2 and a separation of...

A parallel plate, air filled capacitor, has plates of area 0.82 m2 and a separation of 0.040 mm. (a) Find the capacitance. (b) If a voltage of 25 volts is applied to the capacitor, what is the magnitude of the charge on each plate? (c) What is the energy stored in the capacitor? Now the plates are filled with strontium titanate having a dielectric constant of 310 and a dielectric strength of 8.0 kV/mm. (d) What is the new value...

A parallel plate capacitor has circular plates of diameter 5 cm and separation 2 mm. The...

A parallel plate capacitor has circular plates of diameter 5 cm and separation 2 mm. The space between the plates is filled with a material of dielectric constant K = 3. The charges on the plates are ± q. The charge is given by q = 27 × 10−9 C. Find: (i) the charge; (ii) the capacitance; (iii) the potential difference between the plates; (iv) the magnitude of the electric field between the plates; (v) the electric energy density between...

An air-filled parallel-plate capacitor has plates of area 2.50 cm separated by 1.00 mm. The capacitor...

An air-filled parallel-plate capacitor has plates of area 2.50 cm2 separated by 1.00 mm. The capacitor is connected to a 24.0-V battery. (a) Find the value of its capacitance._______ pF (b) What is the charge on the capacitor? _______ pC (c) What is the magnitude of the uniform electric field between the plates? _______ V/m

The parallel-plates in a capacitor, with a plate area 1.2×10−3 cm2 and an air-filled separation of...

The parallel-plates in a capacitor, with a plate area 1.2×10−3 cm2 and an air-filled separation of 10 mm, are charged by a 12 V battery. They are then disconnected from the battery and pushed together (without discharge) to a separation of 3.5 mm. (a) Find the initial potential difference between the plates and the initial stored energy. (6 points) (b) Find the final potential difference between the plates and the final stored energy. (6 points) (c) How much work is...

An air-filled parallel-plate capacitor has plates of area 2.40 cm^2 separated by 3.00 mm. The capacitor...

An air-filled parallel-plate capacitor has plates of area 2.40 cm^2 separated by 3.00 mm. The capacitor is connected to a(n) 23.0 V battery. (a) Find the value of its capacitance. pF (b) What is the charge on the capacitor? pC (c) What is the magnitude of the uniform electric field between the plates? N/C

A parallel plate capacitor consisting of square plates is charged. One edge of the plates is...

A parallel plate capacitor consisting of square plates is charged. One edge of the plates is 0.4 (m). When the current is 5 (A), the rate of change of the electric field between the plates is approximately how many V / (m.s). Eo = 8.85x10-12 (SI)

A parallel-plate vacuum capacitor has 7.22J of energy stored in it. The separation between the plates...

A parallel-plate vacuum capacitor has 7.22J of energy stored in it. The separation between the plates is 2.70mm . If the separation is decreased to 1.85mm , a) what is the energy now stored if the capacitor was disconnected from the potential source before the separation of the plates was changed? b) What is the energy now stored if the capacitor remained connected to the potential source while the separation of the plates was changed?

A parallel plate capacitor has an area of A=200 cm^-2 and 0.50 cm plate distance....

A parallel plate capacitor has an area of A=200 cm^-2 and 0.50 cm plate distance. The capacitor is firstly connected to a power supply that has potential difference V0=30V and after charged the power supply is disconnected. After then a sheet of insulating plastic material is inserted between the plates (completely filling the space between them). With the plastic material the potential difference decreases to 10 V while the charge on capacitor remains the constant. Find ; a)...

Question