Question

A parallel-plate capacitor with plate separation of 1.0 cm has square plates, each with an area of 6.0 × 10 -2 m 2. What is the capacitance of this capacitor if a dielectric material with a dielectric constant of 2.4 is placed between the plates, completely filling them? ( ε 0 = 8.85 × 10 -12 C 2/N ∙ m 2)

A)1.3 × 10-12 F

B)1.3 × 10-10 F

C)64 × 10-14 F

D)15 × 10-12 F

E)15 × 10-14 F

Answer 1

Consider the parallel plate at distance d and area A then we know electric field for a plate is given by,

E=surface charge density/2*£

The two plates have opposite charge. So the electric field will be added to each other..