In: Biology
1. The correct answer is option D i.e. UAA, UAG, and UGA. Three release factors bind to these codons, block translation, and stimulates hydrolysis of the newly formed polypeptide chain attached to the t-RNA located at the P-site.
Eukaryotic termination occurs when ribosome encounters stop codon (UAG, UAA, UGA) and hydrolyzes peptide bond between tRNA in the p-site and growing peptide chain. Stop codons do not bind to tRNA but rather to eukaryotic release factor 1 (eRF1), a factor rebound to eRF3 and GTP. All three of these are necessary as eRF3 induces GTP hydrolysis, which facilitates a conformational change in eRF1, allowing it to hydrolyze the polypeptide chain.
2. The correct answer is option A i.e. blocks the "A" site. Tetracycline inhibits protein synthesis by blocking the attachment of charged aminoacyl-tRNA to the A site on the ribosome.
3. The correct answer is option E i.e. misreading of the genetic frames. Streptomycin is an aminoglycosides that bind to sites on the 30S ribosomal subunit and cause the misreading of genetic code that leads to abnormal proteins; thus they inhibit peptide initiation and elongation.