In: Math
A simple random sample of 33 men from a normally distributed population results in a standard deviation of 8.2 beats per minute. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute. Use the sample results with a 0.10 significance level to test the claim that pulse rates of men have a standard deviation equal to 10 beats per minute. Complete parts (a) through (d) below.
a. Identify the null and alternative hypotheses.
b. Compute the test statistic; χ2 = ___ (Round to three decimal places as needed.)
c. Find the P-value; P-value = ____ (Round to four decimal places as needed.)
d. State the conclusion. (choose one from each ( x, y) set)
Data Summary
s = 8.2 beats per minute Sample standard
deviation
n = 33 Sample size of men
σ = 10 beats per minute Population or standardized
standard deviation
α = 0.10 Level of
significance
a) To test the given hypothesis, we will use a
two-tailed test.
Since we want to test if the standard deviation is equal(or not
equal) to 10 beats per
minute
Hence the null and alternative hypothesis are
Ho : σ = 10
HA : σ ≠ 10
b) χ2 test statistic is calculated as given
below
χ2 =
21.517
c) df = degrees of freedom = n - 1 = 33 - 1 =
32
we find the p-value using Excel function CHISQ.DIST.RT(chisquare
statistic, df)
Since it is a two sided test we do 2*(1 - CHISQ.DIST.RT(chisquare
statistic, df))
p-value = 2*(1 - CHISQ.DIST.RT(21.517,
32))
= 0.1606
P-value =
0.1606
d) 0.1606 > 0.10
that is p-value > α
Hence, we DO NOT reject
Ho
Conclusion
:
Pulse rates of men have a standard deviation equal to 10
beats per minute
Note to
student : You have not provided the (x,y)
set
Hence choose the correct option according to the conclusion
provided
above