Question

A simple random sample of

4444

men from a normally distributed population results in a standard deviation of

7.77.7

beats per minute. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal​ range, the result is a standard deviation of

1010

beats per minute. Use the sample results with a

0.050.05

significance level to test the claim that pulse rates of men have a standard deviation equal to

1010

beats per minute. Complete parts​ (a) through​ (d) below.

a. Identify the null and alternative hypotheses. Choose the correct answer below.

A.

Upper H 0 : sigma greater than or equals 10H0: σ≥10

beats per minute

Upper H 1 : sigma less than 10H1: σ<10

beats per minute

B.

Upper H 0 : sigma equals 10H0: σ=10

beats per minute

Upper H 1 : sigma less than 10H1: σ<10

beats per minute

C.

Upper H 0 : sigma not equals 10H0: σ≠10

beats per minute

Upper H 1 : sigma equals 10H1: σ=10

beats per minute

D.

Upper H 0 : sigma equals 10H0: σ=10

beats per minute

Upper H 1 : sigma not equals 10H1: σ≠10

beats per minuteYour answer is correct.

b. Compute the test statistic.

chi squaredχ2equals=25.49525.495

​(Round to three decimal places as​ needed.)

c. Find the​ P-value.

​P-valueequals=0.03120.0312

​(Round to four decimal places as​ needed.)

d. State the conclusion.

Reject

Upper H 0H0​,

because the​ P-value is

less than or equal to

the level of significance. There is

sufficient

evidence to warrant rejection of the claim that the standard deviation of​ men's pulse rates is equal to

1010

beats per minute.

how to find the p-vaule ?

step by step please

Answer 1

There is sufficient evidence to warrant rejection of the claim that the standard deviation of​ men's pulse rates is equal to10 beats per minute.